# Foo - What is this question asking?!

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View Full Version : What is this question asking?!

phantomcow2
07-08-08, 06:55 PM
Solve the equation http://web-homework.sr.unh.edu/webwork2_files/tmp/equations/86/f678bf70769f3a6330bea8e9a5dfcf1.png = 9 for x

phantomcow2
07-08-08, 06:56 PM
I'd show what work I have done, but I don't even know what my objective is. I am prompted to enter a value for x in the answer box.

FightingPanther
07-08-08, 07:00 PM

just multiply both sides by cx+d and then just simplify

cooker
07-08-08, 07:01 PM
edited out my answer - you have to do it yourself.

get rid of denominator. Get all terms with x on one side of the equation, them extract the x.

phantomcow2
07-08-08, 07:03 PM
Alright, but I'm not sure what I am trying to do here. Am I just trying to isolate x? Where does the 9 even play in?

phantomcow2
07-08-08, 07:04 PM
And cooker, that is correct.

x136
07-08-08, 07:15 PM
Am I just trying to isolate x?You won't take me alive, copper.

Sledbikes
07-08-08, 07:32 PM

deraltekluge
07-08-08, 09:43 PM
When the problem is stated as "solve ... for x", the desired answer is of the form

x = ...

and you get there by manipulating the equation using the rules of algebra, such as:

you can add, subtract, multiply, or divide as long as you do the same thing on both sides of the equals sign, thus maintaining the equality

you can multiply or divide both the numerator and denominator of a fraction by the same thing...that is, multiply the fraction by 1.

For http://web-homework.sr.unh.edu/webwork2_files/tmp/equations/86/f678bf70769f3a6330bea8e9a5dfcf1.png

you should start by multiplying both sides of the equation by (cx + d)

Wordbiker
07-08-08, 10:14 PM
LOL @ posting your homework in Foo.

KrisPistofferson
07-08-08, 10:15 PM
It creates a wight of extraordinary magical power.