Originally Posted by sim0n
<math nerd> its actually the tangent of the angle </math nerd>
Originally Posted by Tom Stormcrowe
<Nerdy>Easiest way is Rise/Run to estimate average slope (or grade). </nerdy>
Thanks. I will see if I have my Trig book from long ago to confirm I understand what you say, about the tangent thing.
If I grasped Tom's simplified explanation and previous answers, then I would guesstimate the difference between the beginning elevation and the destination elevation, then divide by the distance traveled to reach the higher point (in same measure) and then multiply by 100, I have my percentage of the hill.
As experienced Saturday, the estimated hill height is 50 feet from the base, and the road surface traveled was .2 of a mile to reach the crest. Convert .2 of a mile to feet, .1 of 5280 = 528, so .2 = 1,056.
50 / 1056 = .0473 * 100 = 4.73 % incline.
A hill from back home I climbed almost daily on trusty Huffy (single speed), fun to go down, not fun to return home, was listed at 88 feet. The distance to climb is a quarter of mile, .25.
88 / 1320 = .0666 * 100 = 6.66 %
It has been cut down twice, the paper indicated 30 feet had been trimmed off the hill in the past 20 years for safety reasons.
58 / 1320 = .0439 * 100 = 4.39 % still a good work out.
The home I grew up on, (mom still resides there), is about half way up a hill as tall, but stepped, making it easier to travel.
This is interesting.
Of course if I am incorrect in my understanding of how explained please correct, it has been 37 years since trig course in school, and then likely did not understand theroy then , but now can apply then of interest.