If you can, please simplify this expression:
SQRT(X^2 + Y^2) * COS(45 - ATAN(Y/X))
The expression in the COS( ) looks familiar to me, but it has been 10 years since I finished my engineering degree. Thanks!
If you can, please simplify this expression:
SQRT(X^2 + Y^2) * COS(45 - ATAN(Y/X))
The expression in the COS( ) looks familiar to me, but it has been 10 years since I finished my engineering degree. Thanks!
...
42
I removed all the unnecesasry stuff and got the answer to your math problemOriginally Posted by Towlie
Are you a registered member? Why not? Click here to register. It's free and only takes 27 seconds! Help out the forums, abide by our community guidelines.
Please, express the answer in terms of X and Y only; no supernatural deities.
...
This ain't homework. The question is directed to math majors, not math phobics. This is not an advanced problem in the grand scheme of things; I am simply rusty on my trig and algebra.
...
what else ..... and thanks for the fish.Originally Posted by Taerom
No it's not advanced....never said it was. I'm not a math phobic by ANY stretch of the definition (I have a bachelors and masters degree in computer engineering...methinks I've taken some math courses).....I still think it looks like you are trying to get help with a homework problem.Originally Posted by Towlie
I am 33 yrs old; I am not doing homework; I am a BSME (UT Austin, May, 1997)....I derived this expression trigonometrically on a project I am working on, and I don't know/remember how to simplify it.
I don't remember all the trigonometric identities because I haven't worked with them for a long while, e.g.
http://www.sosmath.com/trig/Trig5/trig5/trig5.html
...
43!Originally Posted by KingTermite
I don't think I could simplify it further myself, but I'm not very good at math anyway. Why can't you use it as it is?
Click to see the current weather conditions where I live!
Drink! Feck! Arse! Girls!
I guess I could - but if there were a generally known trigonometric identity in the field, it might look dumb for me to express it in an unnecessarily complicated fashion (e.g., to make something up, suppose everythinig in the parantheses could be replaced by cos(x/y) or something simple like that).
...
I'm only calling it how it looked. See it from "our" point of view. Too many kids come on here and try to get help with their homework....quite often. It would be good for you to explain your situation so we don't think (like I did) that you are a 16 year old looking for homework help. I'm sorry if I offended....but that sure is how it looked.Originally Posted by Towlie
whats up with people and hitchikers guide to the galaxyOriginally Posted by scrapmetal
hi
If you actually have a BSME, then you should now how to do this as a matter of course imo. Nothing scares me more than engineering majors that don't know their shiz, because it's an applied skill. Unlike something like english, or even pure math, where screw ups can result in poor marks or scathing peer reviews, but shiz can't really go that bad from a practical perspective. Heh, ManBearPig.
(X±Y)1/2*COS[45-ATANG(Y/X)]Originally Posted by Towlie
=(X±Y)(X±Y)(COS)(45-X/Y)?
I think that's how it would factor out.
. “He who fights with monsters might take care lest he thereby become a monster. And if you gaze for long into an abyss, the abyss gazes also into you.”- Fredrick Nietzsche
"We can judge the heart of a man by his treatment of animals." - Immanuel Kant
It'll give you the length of the vector from the origin to (x,y) projected onto the line x = y.
Though that might be how you derived it in the first place! Simplifying it?
Hmm, thinking dot product could be useful, (also thinking as typing so bear with me).
(x,y).(0.707, 0.707) = 0.707x + 0.707y
excel confirms.
where 0.707 is actually meant to be 1/sqrt(2)
Possible complications outside of the range 0-90 degrees due to the atan not being unique. Can't be bothered to think that hard though.
Apologies to those arguing the poster should have solved it themselves. But I needed some mental exercise due to having been laid up in hospital for four weeks avoiding my maths lectures.
edit:
Just managed it properly too.
let sqrt() denote SQRT(X^2 + Y^2) for easy writing.
SQRT(X^2 + Y^2) * COS(45 - ATAN(Y/X))
=sqrt() * [ cos(45)*cos(atan(y/x) + sin(45)*sin(atan(y/x)]
=sqrt() * [ 0.707 * x / sqrt() + 0.707 * y / sqrt() ]
=0.707 * (x + y)
Last edited by j-dowsett; 05-22-07 at 08:01 AM.
Originally Posted by j-dowsett
Thanks, man. I actually logged in because I found the answer on my own and wanted to post it. The result I found was (X+Y) / SQRT(2). Soooooo simple. I found the answer numerically, plugging in numbers into a table and playing around with them.
...
Where are you trying to get to? The Atan will give you and angle that you then subtract from 45° get the Cos of that ...Originally Posted by Towlie
So as long as you know x&y things should be ok. Or are you trying to use this to determine x&y?
Joe
I have no idea, I got lost at that point!Originally Posted by joeprim
. “He who fights with monsters might take care lest he thereby become a monster. And if you gaze for long into an abyss, the abyss gazes also into you.”- Fredrick Nietzsche
"We can judge the heart of a man by his treatment of animals." - Immanuel Kant