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Old 04-03-08, 07:57 PM   #1
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Algebra Hlep Please

Hlep me with this Albebra.
This is not factorable, correct?

30x squared + 11x - 30 = 0

It is not factorable, right?
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Old 04-03-08, 08:10 PM   #2
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Incorrect.

(5x+6)(6x-5)
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Old 04-03-08, 08:10 PM   #3
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Thanks
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Old 04-03-08, 08:11 PM   #4
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Can you explain por favor?
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Old 04-03-08, 08:12 PM   #5
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Can you explain por favor?
oh god... do some #$%ing reading in your book, and dont say it doesnt explain it...
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Old 04-03-08, 08:15 PM   #6
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oh god... do some #$%ing reading in your book, and dont say it doesnt explain it...
What is this "reading" you speak of?
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Old 04-03-08, 08:24 PM   #7
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(-b +- sqrt( b^2 - 4ac))/2a will also tell you of its factors.
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Old 04-03-08, 08:32 PM   #8
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The QUADRATIC FORMULA didn't work for me.
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Old 04-03-08, 08:37 PM   #9
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The factors, if any, would be of the form (Ax+B) and (Cx+D), where

AC=30

BD=-30

AD+BC=11.

There aren't many pairs of numbers that, when multiplied together, give you 30. These pairs are 1 & 30, 2 & 15, 3 & 10, 5 & 6. One of those pairs will be your choice for A & C, and one pair (possibly the same pair) will be your B & D (actually, B or D will be the negative of one of the numbers in one of the pairs).

You just have to start testing different combinations of these pairs. You don't even need to worry about the negative sign at first. Just look for pairs such that the product of one number in one pair and one number in the other pair is 11 away from the product of the other number in each pair. For example, take the pairs 5 & 6 and 5 & 6. 5*5=25, 6*6=36. Their difference is 11.

Go on to figure out where the negative sign goes.
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Old 04-03-08, 08:37 PM   #10
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The QUADRATIC FORMULA didn't work for me.
How so?

-11 +- sqrt(121+3600)/60 right? whats not working in that equation?

it gives you (-11+- 61)/60 which yields 5/6 and 6/5

x=5/6 => 6x-5=0
x=6/5 => 5x-6=0
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Old 04-03-08, 08:39 PM   #11
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Why are you doing his homework? Cryptic hints and guidance is what he needs That way he thinks it through and really learns
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Old 04-03-08, 08:45 PM   #12
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Why are you doing his homework? Cryptic hints and guidance is what he needs That way he thinks it through and really learns
I have everything done except for this problem, I got stuck on it. I was studying for finals (tomorrow) and I couldn't get past this.
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Old 04-03-08, 08:49 PM   #13
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Teasing you Max

You'll kick butt on the exam....relax and do the easy problems first and then go back and rework the problems you got stuck on. That way, you'll get more done if you run into time issues. Also, the easier problems will often give you hints on the harder ones. Strategy AND knowlege.

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I have everything done except for this problem, I got stuck on it. I was studying for finals (tomorrow) and I couldn't get past this.
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Old 04-03-08, 08:54 PM   #14
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Teasing you Max

You'll kick butt on the exam....relax and do the easy problems first and then go back and rework the problems you got stuck on. That way, you'll get more done if you run into time issues. Also, the easier problems will often give you hints on the harder ones. Strategy AND knowlege.
All problems are easy problems for me
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Old 04-03-08, 09:11 PM   #15
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All problems are easy problems for me
Except the one you just got stuck on......
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Old 04-03-08, 09:12 PM   #16
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Except the one you just got stuck on......
Nah, I was just testing you guys
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Old 04-03-08, 09:16 PM   #17
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You'll kick butt on the exam.
Nope. He just wont.
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Old 04-03-08, 11:46 PM   #18
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Nope. He just wont.
You fail at life.

Go die.

I am offended by your comment.
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Old 04-03-08, 11:49 PM   #19
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Any polynomial that can be expressed in "Ax^2 + Bx + C" (assuming A, B, and C are rational numbers) can be factored via the quadratic formula. It may be ugly, bristling with square roots, but it can be done.
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Old 04-03-08, 11:50 PM   #20
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You spelt help wrong, what do you expect?
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Old 04-03-08, 11:51 PM   #21
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You spelt help wrong, what do you expect?
I did that on purpose.
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Old 04-03-08, 11:53 PM   #22
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And Algebra too, right? Of course what was I thinking.
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Old 04-04-08, 07:55 AM   #23
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The QUADRATIC FORMULA didn't work for me.
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.... Other than being completely wrong, you're correct.
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Old 04-04-08, 08:05 AM   #24
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I did that on purpose.


yeah, so did these guys.
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Phobias are for irrational fears. Fear of junk ripping badgers is perfectly rational. Those things are nasty.
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Old 04-04-08, 08:09 AM   #25
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