(8x^-12 y^24/27z^-18)^1/3
Simplify each expression leaving only positive exponents.
I don't even know where to start
can I multiply each exponent by 1/3?
(8x^-12 y^24/27z^-18)^1/3
Simplify each expression leaving only positive exponents.
I don't even know where to start
can I multiply each exponent by 1/3?
I'm cool with that...This is just the stuff I'm already supposed to know Haven't had a math class in 14 years and it wasn't this advanced...
start out by cubing the expression to get rid of the exponent.
so it would be like this?
(8x^-12y^24/27z^-28)
I don't see how you can do that, though.
you are trying to establish, what is the cube root of that equation. Calculate the cube root of the top and the bottom separately.
pssst! The answers are in the back of the book.
Just distribute the 1/3 exponent through, and remember what a negative exponent means (and how you make it "positive")
Ok. so the top
(8x^-12 y^24)^1/3
(8x^-4 y^8) ?
I wish I had a book. this is a worksheet...blargh
Since (x/y)^ 1/3 = (X ^ 1/3) / (y ^ 1/3)
8x^-12 y^24/27z^-18)^1/3 = [(8x^-12 y^24)^1/3] / [(27z^-18)^1/3]
It should be pretty straight forward to simplify the numerator and denominator...
Then figure out how to make the negative exponents positive...
Slow Ride Cyclists of NEPA
People do not seem to realize that their opinion of the world is also a confession of character.
- Ralph Waldo Emerson
Slow Ride Cyclists of NEPA
People do not seem to realize that their opinion of the world is also a confession of character.
- Ralph Waldo Emerson
Slow Ride Cyclists of NEPA
People do not seem to realize that their opinion of the world is also a confession of character.
- Ralph Waldo Emerson
I'm possibly getting a job with a local university in which case i get to take classes for free. I think math is my next area of study
oh yeah, right. all the forms get raised to the power of 1/3. cool so the top is
(2x^-3 y^8)/(3z^-6)
So now I need to figure out how to flip the exponent signs. Can I do this?
(2z^6 y^8)/(3x^3) ?
Indeed you can...
Since x^-1 = 1/x
Slow Ride Cyclists of NEPA
People do not seem to realize that their opinion of the world is also a confession of character.
- Ralph Waldo Emerson
WooHoo! that's 2 out of...let me see here...er...20...
What makes these easier is finding the set of (mathematical) tools that you can use for each situation
So for exponents, a few tools include:
for any value of a and b
a^b + a^b = 2*(a^b)
a^b * a^1 = a^(b+1) which is the same as a^b * a^b = a^2b
a^-b = 1/(a^b)
a^(1/2) = the square root of a
a^(1/3) = the cude root of a
a^(2/3) = the cube root of a^2
and so on
A good ride is one you can walk away from.
A great ride is one where you can still use the bike afterwards.
Learn from the mistakes of others.
You won’t live long enough to make all of them yourself.
Sorry that there are so many formulas, but i find that if you know how to use the formulas, you can dissect the problem into smaller, easier problems
A good ride is one you can walk away from.
A great ride is one where you can still use the bike afterwards.
Learn from the mistakes of others.
You won’t live long enough to make all of them yourself.
Yeah, Cool thanks...I'll have to write them down (it's easier to see it that way)
You seem like such a nice kid from your posts. Why would you want to do this to yourself?