geeze. this chemistry stuff is like the english language: more exceptions than rules. Anyways..

A 27.0 g sample of ethylene glycol, a car radiator coolant, loses 690. J of heat. What was the initial temperature of ethylene glycol if the final temperature is 32.5°C? (c of ethylene glycol = 2.42 J/g·K)

So. The formula is J=(c)(mass)(change in T). So I solved for Ti and came up with Ti=Tf-J/(c)(mass). And I came up with 21.9 degrees centigrade for the answer. Only problem is, this answer is wrong.

Help. me. Please.