Rudimentary question about finding upper/lower bound of integral
Okay I am taking Calculus 2 this summer at my local university. It's a summer course so it's faster and therefore harder. I don't have a lot of access to help
Use the min-max inequality to find the upper and lower bounds for the value of the integral from 0 to 1 of 1/(1-t^2)
the lower bound can be found by f(minimum) * (b-a) and the upper by f(maximum) * (b-a)
So when they say f(min) and max, what exactly do they mean? To find a function's minimum I would set the first derivative equal to zero. Do I plug this x value -- where the minimum occurs at -- or the y value, what the minimum value is, into the equation?