Calculus math problem
How do you do the following:
Find y' (y prime)
I have no clue how to do this problem
I think they want you to find the derivative ( ' ), ie find dy/dx if y=......
Take the natural log of both sides (ln). Then you can take the (1/x) down to the front of the ln(tanx). Then take the dirivative of both sides.
Originally Posted by Wordbiker
I found y'. It is in the second line of your post...
When you do this and solve for yprime, you sill may have a y somewhere in your equation. You simply substitute your origional equation for y so you have a function of x only.
Originally Posted by Hickeydog
Use the chain rule, then the quotient rule, then the chain rule again...
Just a hint:
tanx^(1/x) = exp(1/x ln tanx) and the exponential chain rule d exp(u)/du * du/dx where u = 1/x ln(tanx)
Last edited by ehidle; 10-08-09 at 07:14 PM.