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  1. #1
    la vache fantôme phantomcow2's Avatar
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    Would a trig expert please help?

    Im trying to figure out these stupid inverse functions in trig. I know Soh Cah Toa. And im good with that but now its stuff where instead of being given the value of your angle (theta) and the value of one length and you find the rest. Its 2 lengths and you find the angle.
    So heres the problem:
    A cable 4m long is attached to a pole. This cable is staked to the ground 1.75m from the base of the pole. Find the angle that the cable makes with the ground.
    I used the bottom left angle as my theta. I think its the Sin -1 function i have to use since sin is opposite over hypotenuse.

    So what i thought to so was Sin -1( 1.75 divided by 4
    I came up with 25.94 (rounded slightly)

    / |
    4 / |
    / | 1.75
    / |
    / |
    /_______|

    Can somebody tell me if this is right or not?
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  2. #2
    la vache fantôme phantomcow2's Avatar
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    eeeh the triangle turned out not so great
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  3. #3
    la vache fantôme phantomcow2's Avatar
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    Soh Cah Toa? Smeans Sin. and oh menas opposite over hyp
    Cosin and the ah means adjacent over hyp
    Tangent means opposite over adjacent
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  4. #4
    la vache fantôme phantomcow2's Avatar
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    Yea I can photoshop the triangle
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  5. #5
    la vache fantôme phantomcow2's Avatar
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    do you get 25.94 when rounded to the nearest hundred?
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  6. #6
    la vache fantôme phantomcow2's Avatar
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    Soh Cah Toa is what every teacher except this one ***** teaches. For hte intro and the trig class
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  7. #7
    la vache fantôme phantomcow2's Avatar
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    well in geometry class part of the cericulum is intro to trig. Its supposed to be just 4 days. bUt the teacher i have is the biggest math geek ever and is qualified to teach every math course this school offers. He teaches AP stat and trig, and that is what he is more happy with so instead of 4 days we spend 4 weeks
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  8. #8
    Senior Member LordOpie's Avatar
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    Quote Originally Posted by MERTON
    what's intro?
    Use "intro" in a sentence...

    Intro.

    Phantom is going to intro his boot to Merton's butt.

    Intro.


    PS: Calc and higher maths are easy if you're solid with algebra and trig

  9. #9
    la vache fantôme phantomcow2's Avatar
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    yea yea i know. IM actually doing well in trig. I enjoy it a hell of a lot more than proofs!
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  10. #10
    Senior Member LordOpie's Avatar
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    for those who don't know, curly hair notation = pubic short-hand.

  11. #11
    Chronic Tai Shan ofofhy's Avatar
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    Some Old Horse Caught Another Horse Taking Oats Away

    a/sinA = b/sinB = c/sinC, where A is an angle, and a is side of triangle opposite angle A, and so on.

    Works for any triangle.
    From Craig's List: IF its a singlespeed that means----all the other parts are broken cut off and dumped...dont buy singlespeeds, the bikes will make your balls fall off

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  12. #12
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    Quote Originally Posted by phantomcow2
    Im trying to figure out these stupid inverse functions in trig. I know Soh Cah Toa. And im good with that but now its stuff where instead of being given the value of your angle (theta) and the value of one length and you find the rest. Its 2 lengths and you find the angle.
    So heres the problem:
    A cable 4m long is attached to a pole. This cable is staked to the ground 1.75m from the base of the pole. Find the angle that the cable makes with the ground.
    I used the bottom left angle as my theta. I think its the Sin -1 function i have to use since sin is opposite over hypotenuse.

    So what i thought to so was Sin -1( 1.75 divided by 4
    I came up with 25.94 (rounded slightly)

    / |
    4 / |
    / | 1.75
    / |
    / |
    /_______|

    Can somebody tell me if this is right or not?

    what you actually found was the angle the cable makes the pole. in the picture, you drew 1.75m as the height of the pole, instead of the distance from the stake to the base of the pole. which might have confused you. the answer you found is right for the picture you drew. however, since 1.75 is the base of the triagle...what you're looking for is cos^-1(1.75/4) which should give you ~64.06 deg.

  13. #13
    My life be like ooh aah anthonaut's Avatar
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    Quote Originally Posted by phantomcow2
    Im trying to figure out these stupid inverse functions in trig. I know Soh Cah Toa. And im good with that but now its stuff where instead of being given the value of your angle (theta) and the value of one length and you find the rest. Its 2 lengths and you find the angle.
    So heres the problem:
    A cable 4m long is attached to a pole. This cable is staked to the ground 1.75m from the base of the pole. Find the angle that the cable makes with the ground.
    I used the bottom left angle as my theta. I think its the Sin -1 function i have to use since sin is opposite over hypotenuse.

    So what i thought to so was Sin -1( 1.75 divided by 4
    I came up with 25.94 (rounded slightly)

    / |
    4 / |
    / | 1.75
    / |
    / |
    /_______|

    Can somebody tell me if this is right or not?
    Easy. You make the angle you need to find theta (the angle the cable makes with the ground) and the it becomes:

    cos theta = 1.75/4
    theta = cos^-1 (1.75/4)

    Punch that into your calculator and you're done.
    Any true downhiller can huck, but no hucker can truly downhill - Ryan N.

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  14. #14
    cab horn
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    We'll easily solve this problem for you.

    Go to paint. Draw out the diagram. Save as jpeg. Upload to any webspace and reference it here.

  15. #15
    Senior Member FXjohn's Avatar
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    Quote Originally Posted by phantomcow2
    Im trying to figure out these stupid inverse functions in trig. I know Soh Cah Toa. And im good with that but now its stuff where instead of being given the value of your angle (theta) and the value of one length and you find the rest. Its 2 lengths and you find the angle.
    So heres the problem:
    A cable 4m long is attached to a pole. This cable is staked to the ground 1.75m from the base of the pole. Find the angle that the cable makes with the ground.
    I used the bottom left angle as my theta. I think its the Sin -1 function i have to use since sin is opposite over hypotenuse.

    So what i thought to so was Sin -1( 1.75 divided by 4
    I came up with 25.94 (rounded slightly)

    / |
    4 / |
    / | 1.75
    / |
    / |
    /_______|

    Can somebody tell me if this is right or not?
    Just draw it out on Autocad (you said you used) and measure.

  16. #16
    Chronic Tai Shan ofofhy's Avatar
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    Quote Originally Posted by MERTON
    you can see the pic just fine if you click on his quote button.
    The problem is that the diagram in his original post does not match the wording of the problem. It should be like the attached. Anthonaut and apple_quit are right.
    From Craig's List: IF its a singlespeed that means----all the other parts are broken cut off and dumped...dont buy singlespeeds, the bikes will make your balls fall off

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  17. #17
    Chronic Tai Shan ofofhy's Avatar
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    Quote Originally Posted by MERTON
    oh. heh. i really need to start reading.
    RIF
    From Craig's List: IF its a singlespeed that means----all the other parts are broken cut off and dumped...dont buy singlespeeds, the bikes will make your balls fall off

    * no -- it's NOT ok to contact this poster with services or other commercial interests

  18. #18
    Chronic Tai Shan ofofhy's Avatar
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    Quote Originally Posted by MERTON
    read it first?
    Reading Is Fundamental
    From Craig's List: IF its a singlespeed that means----all the other parts are broken cut off and dumped...dont buy singlespeeds, the bikes will make your balls fall off

    * no -- it's NOT ok to contact this poster with services or other commercial interests

  19. #19
    la vache fantôme phantomcow2's Avatar
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    i dont need to use autocad. I get it all now,
    C://dos
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  20. #20
    My life be like ooh aah anthonaut's Avatar
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    Quote Originally Posted by ofofhy
    The problem is that the diagram in his original post does not match the wording of the problem. It should be like the attached. Anthonaut and apple_quit are right.
    Yay! My Trig teacher would be proud of me.
    Any true downhiller can huck, but no hucker can truly downhill - Ryan N.

    Mtbworld - http://mtbworld.mybesthost.com

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