Hope anybody could explain me this...
Ok i been having this doubt for zillions of years and I need somebody to explain it to me ok?
This is the deal...
For example, steel frame with 73 degrees st angle, front tube 73 degrees also. Now, of you make an imaginary line (parallel to the ground and tt) between the rear and front dropouts, the intersection with the seat tube with this imaginary line has a different angle, not 73 degrees, lets say 72.8 or whatever... why is that??? Anybody knows the reason?
By geometry it should be the same angle, opposite angles between parallel lines, but looks like in bikes is not like that, anybody?
with older "horizontal" dropouts, the rear dropout height could vary depending on the wheel position. If the fork was replaced, that could vary the effective ht/st angles. I can't think of any other thing other than some sort of construction error. I'm sure there are plenty of bikes out there with issues along those lines, it's easy to do.
The baseline is a line through the centers of the rear dropout and the front fork dropout. Everything is relative to that baseline (STA, HTA, BB drop). If the rear dropout is "horizontal" similar to the Campy 1010, the wheel axle can be above the baseline if it's positioned at the rear of the dropout, or below the baseline if it's positioned at the forward end of the dropout. Similarly, if the fork is longer or shorter, or has a different headset than the frame designer assumed while designing the frame, the fork dropout could be higher or lower than the designed baseline. Slight changes in where the baseline is (as opposed to where it should be according to the design) will change the angles of the seat tube and head tube relative to the ground since the actual baseline is no longer parallel to the ground.
EDIT - unterhausen beat me to it.
I'm asking because a builder told me this centuries ago and now looking to some geometry draws the baseline and the tt/st angles are effectively different...
for example the 1973 raleigh professional track frame... a classic..
The seat tube angle is 73.3 and the other angle is 74... so this has something to do with the BB height then? as higher the BB shell the bigger the angle.
This is from where i got this...
I have no idea why they would do that, but the top tube isn't level. Maybe to lower the handlebars, or maybe because they messed up and didn't feel like fixing the drawing.
In your drawing, the top tube is not parallel to the baseline, so the top tube-to-head tube angle and the top tube-to-seat tube angle will not be the same as the head tube-to-baseline angle (HTA) and seat tube-to-baseline angle (STA). The frame in your drawing has parallel head tube and seat tube (both are 74 degrees from the baseline).
The BB drop is the vertical distance from the baseline to the center of the BB shell. The BB height will depend on what size wheels and tires you use.
as the wheel is moved back in that dropout, the tt will get closer to horizontal
Hmm... dudes it is so odd... for example i have this other drawing from another place, same situation, in this case the bb is lower tho...
If the tt is not parallel to the base line then the st/tt and tt/ht should be different, not equal, m'i wrong?
I would guess it's related to the fork offset. A proper parallelogram exists between the TT, ST, Steerer, and your imaginary line. When you offset the fork perpendicular to the steering axis, you raise up your imaginary line just a bit.
as long as the HT/ST are parallel, the st/tt and ht/tt angle have to be equal. As the predominance of slanted top tube bikes shows, there is no significance to the top tube angle to the ground. The steering geometry of the frame is determined by the fork rake and head angle and wheelbase. Everything else about the geometry is there to hold the rider off of the wheels.
Originally Posted by ultraman6970