Me too. See how that doesn't qualify me as an expert in bicycle science?

Break out the math. Assume rider weight is constant, and disregard frame weight as it is an unknown and possibly equal. I think that means we can simplify things to just the wheel/tire combination. Figure 2" tires on the 26" wheel and 35mm tires on the 700c wheel. The larger diameter (by about 32mm at the edge of the tire) of the 700c wheel gives it a rolling resistance advantage, but the wider tire on the 26" wheel will offset that to some degree. Let's assume, for inertia calculations, that the weight of the wheel is uniformly distributed at the rim and the weight of the tire is uniformly distributed at the edge of the tire. Wheel and tire weights are variable. At some weight, I think, there will be an equilibrium between the two wheels where moment of inertia and rolling resistance give them equal acceleration characteristics. Your task is to show that the weight in question is outside the norm for real world wheels. I wouldn't be surprised if you're right, but as they say in Missouri, "Show me."

Obviously, the OP isn't interested in a 26" wheeled bike, so it would seem I'm just debating for the love of mathematics at this point.