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Originally Posted by lawkd
Indeed, please let's do think about this. The axle is not supported by its tiny area of contact with the dropout, regardless of whether that point of contact is curved or straight. The axle is supported (in its full circumference) by the locknut which is held against the dropout by the opposing nut on the quick release. Those two nuts, with knurled surfaces, pinch and hold the dropout. The threaded-on locknut on the inside of the dropout is what holds the axle in place. The quick release just holds that locknut against the dropout and won't let it move. The support of the axle has nothing to do with how much of the dropout "wraps around" the axle. Nothing to do with it. And most certainly, the shape of the dropout has nothing whatsoever to do with axle breakage.
Irrelevant. |
I've been riding and racing bikes since the early 70's and I have never seen any dropout break other then in an accident. So even though the strength thing makes sense, and yes it does make sense, I've never seen a dropout break even on heavy loaded touring bikes or when clydesdales were riding on horizontal dropouts. Maybe that problem may have happened to cheap WallyWorld or Sears bikes etc but not on the better bikes. In fact most bikes I ever saw fail was when strong clydesdale types put too much torque on the frame then the frame would seperate, but most of those breaks happened to older AL frames and the frame snapped usually in the BB area.
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Originally Posted by ridelugs
then why :) do axles break far more often in horizontal drop out arrangements? the quick release is made to purely hold the wheel in place, not to provide structure. i can bend a qr in my hand. we are talking about vertical loads here, not horzontal ones.
Please stop and think for just a moment about what I said. Please. I did NOT say that the quick release bears any of the weight. It does NOT. It simply holds the knurled nuts together, and THEY (the knurled nuts), by *pinching* the dropout opening, support the axle. The only time an axle will contact a dropout in any way traumatic enough to cause it to break, is if it is LOOSE. That is not the case under normal circumstances. The locknut and the quick release nut hold the axle in place, and the locknut, threaded onto the axle, is what supports it. Can you get that? The dropout opening, whether horizontal or vertical, does NOT support the weight of the bike on the axle in any meaningful way. It's a guide for the positioning of the axle, and it provides a structure for the locknuts to grip. That is what it does. Axles typically break at the point where the bearing cone is threaded on, because that is where the stress is. Not in the dropout. |
Ridelugs,
I'll take a stab at answering your question (even though you didn't ask nicely).. Axles break more often on older freewheel hubs, where the drive side bearings are further from the dropout than the non drive side. It just so happens that these hubs are usually in horizontal dropout frames. |
and perhaps to a lesser extent, if a wheel is dished incorrectly, the wheel may be placed in a horizontal dropout crooked in order to centre the rim in the frame. This may put nasty force on the axle, making it more likely to fail.
- Joel |
Originally Posted by lyledriver
Ridelugs,
I'll take a stab at answering your question (even though you didn't ask nicely).. Axles break more often on older freewheel hubs, where the drive side bearings are further from the dropout than the non drive side. It just so happens that these hubs are usually in horizontal dropout frames. |
:rolleyes: :rolleyes: :rolleyes:
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Originally Posted by ridelugs
blah blah that if those same axles were placed in a vertical drop out, thier failure rate would drop exponentially.
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I have vertical dropouts on the 1988 Schwinn mountain bike, horizontal on my road bikes (1959 to 1981). When pushing a rear derailleur to its cog size and chain wrap accommodation limits, horizontal adjustability can be VERY handy.
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