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Originally Posted by zzyzx_xyzzy
(Post 10257012)
I(it may be easier to determine MA in terms of "how far does the output move when I incermentally move the input" rather than "how much force comes out when I put a certain force in." Both methods have to give the same answer but I find the first to be easier to think about when I'm drawing diagrams.)
It seems clear if you lift the yoke in the right hand figure some distance X, the weights will rise the same distance X, hence you will have done work = 1 lb * X. On the left side, it seems that raising the yoke by some distance X, will raise the weights some distance < X, meaning you will have done less work on the left than for an equivalent motion of the yoke on the right. Which is another good way to think about this. |
Okay, I have it.... no, that's not right. Wait! Shouldn't that be .... no... Fazzbazz.
Benno is right. I need to recalibrate my intuition. |
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From the feedback I've received, it seems that most people think that the analysis needed more support for the main equation. Initially, I didn't want to bog down the paper with too much math which I thought would dissuade a lot of people from reading it, so I had avoided this. But after rethinking this I have expanded this section a little and added a footnote with a proof for the main equation.
This is the proof: Attachment 133911 The feedback on the calculator itself, has been great. Thanks for all the feedback and criticism. I hope the analysis is a little more clear now and still readable. |
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