Cycling and bicycle discussion forums. 
   Click here to join our community Log in to access your Control Panel  

Go Back   > >

Bicycle Mechanics Broken bottom bracket? Tacoed wheel? If you're having problems with your bicycle, or just need help fixing a flat, drop in here for the latest on bicycle mechanics & bicycle maintenance.

User Tag List

Thread Tools Search this Thread
Old 02-24-11, 01:16 PM   #1
Senior Member
Thread Starter
Join Date: Jan 2010
Location: France
Posts: 132
Mentioned: 0 Post(s)
Tagged: 0 Thread(s)
Quoted: 0 Post(s)
Sturmey Archer left hand ball ring removal.

On Old sturmey archer hubs you could unscrew the left hand (non cog side) ball ring. Later on they were pressed in. Anyone know if the modern ones are pressed or can be unscrewed?

What i want to do is put an old sturmey FM 4 speed medium ratio internals into a modern alloy shell. I know i could get a whole hub and build it into a wheel but i am afraid of the following:

I am pretty strong so this is a real possibility, especially knowing what i can do to weak wheels... So what i am thinking is buying a modern alloy shell, removing the left hand ball ring, installing the FM one and building it into a new wheel. Any insights or suggestions are highly appreciated. I succesfully converted AW to AM but i do miss the low end.*I think that is why Sturmey made the FM and it was regarded to be the best club gear.

Thank you in advance!

Carcinogent is offline   Reply With Quote

Thread Tools Search this Thread
Search this Thread:

Advanced Search

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

All times are GMT -6. The time now is 09:25 AM.

We are a participant in the Amazon Services LLC Associates Program, an affiliate advertising program designed to provide a means for us to earn fees by linking to and affiliated sites.
  • Ask a Question
    get answers from real people!
Click to start entering your question.