Bike Forums (https://www.bikeforums.net/forum.php)
-   Foo (https://www.bikeforums.net/foo/)

 AchiLLe..s 11-24-08 04:49 PM

Ok I am stumped on these 2 questions.

A thread holds a 1.5-kg and a 4.50-kg cart together. After the thread is burned, a compressed spring pushes the carts apart, giving the 1.5 kg cart a speed of 32 cm/s to the left. What is the velocity of the 4.5-kg cart?

So far my givens are

Mass A= 1.5 kg
Mass B= 4.50 kg
Velocity A= 32 cm/s
Velocity B= X

How am I supposed to find the answer with only thoose givens using the law of conservation of momentum equations? I'm not sure what the velocity final is for either one. I'm really confused.

As for the second question. I have the same problem

Carmen and Judi dock a canoe. 74.0-kg Carmen moves forward at 4.0 m/s as she leaves the canoe to step onto the dock. At what speed and in what direction do the canoe and Judi move if their combined mass is 115 kg? (Use a positive number if the canoe moves away from Judi.)

Givens:

Mass A= 74 kg
Velocity A= 4.0 m/s
Velocity B= X?

This question I am totally clueless as well and would love if someone could point me in the right direction.

Equations:

Ma(Va)+Mb(Vb)= Ma(Vaf)+Mb(Vbf) Elastic equation

Ma(Va)+Mb(Vb)= (Ma+Mb)Vf Inelastic Equation

 FlatMaster 11-24-08 05:12 PM

First one. You're correct that you need to conserve momentum.

p=mv
What is the initial momentum?
velocity is zero, so initial momentum is zero.

What is the final momentum?
Well, both carts have a velocity so momentum must not be zero right??
Wrong!! Remember, momentum is a vector. The cart moving to the right has positive momentum, while the cart moving to the left has negative momentum.

p initial = p final
0 = p final
0 = m1v1 + m2v2

 Zan 11-24-08 05:15 PM

second one = heavy girls

m1v1 = m2v2

(74)(4) = (115)v2

v2 = 74*4/115

pretty much like the first. just remember to take into account direction. choose which is "positive" and the other negative.

i'm actually doing these questions in physics right now.

 Hocam 11-24-08 05:30 PM

My rule for physics "When in doubt, multiply them together"

If that doesn't work, just look at the unit's of the final answer and do some set of operations to what you're given to get the same units.

 AchiLLe..s 11-24-08 06:01 PM

Thank you guys. I understand it a lot better now.

 jschen 11-24-08 09:00 PM

Quote:
 Originally Posted by AchiLLe..s (Post 7911075) How am I supposed to find the answer with only thoose givens using the law of conservation of momentum equations? I'm not sure what the velocity final is for either one. I'm really confused. [...] This question I am totally clueless as well and would love if someone could point me in the right direction.
All these problems are solved EXACTLY the same way.

Step 1: Draw a force diagram. If the solution is now clear, solve the problem.

Step 2: If the solution is not yet clear, draw a clearer, better labeled force diagram. If the solution is now clear, solve the problem.

Step 3: Repeat step 2 as necessary.

 deraltekluge 11-24-08 10:32 PM

Conservation of momentum. If the initial momentum of a system is zero, the total final momentum must be zero, too. You know the mass and final velocity of one part of the system, so you can calculate its momentum. The other part of the system must have a momentum of the same magnitude, but in the opposite direction. You know its mass, so you can calculate its final velocity.

 skinnyone 11-24-08 10:53 PM

Use the conservation of momentum. Think of the 3rd law. Every action has an equal and opposite reaction. Toss in the second law. Profit.

 All times are GMT -6. The time now is 07:56 AM.