Trig Function Question
It's been years since I've worked any trig, and I was working an algebraic equation determining a distance between 2 points when the vectors are on a 90 degree tangent to each other from a common origin point (2 people walking, one at 2 mph and one at 4 mph). If it were a trig question, I'd have a known hypotenuse of 3 miles, and unknown values for a and b, other than b=2a.
I just plain can't remember beyond this point. 
so we know hyp., which is 3 and b=2a
http://faculty.uoit.ca/kay/G10_AppWebPage/ Pythagorean theorem says: c^2=(a^2)+(b^2) since b=2A and c=3, you can substitute it into the equation and write it as 9=(a^2)+(2a^2) 
AAAAH, Thanks! I knew I was on the right track. :p
So, then a=SQRT3 and b=2(SQRT3), then. I ignored the negative result since I was using it for distance in the real world, by the way. 
Two parts couch, one part match. Sorry Tom, I killed my Trig brain cells years ago.
Couch 
no worries, couch. ;) Mine are very rusty. :p

Originally Posted by Tom Stormcrowe
(Post 10397122)
AAAAH, Thanks! I knew I was on the right track. :p
So, then a=SQRT3 and b=2(SQRT3), then. I ignored the negative result since I was using it for distance in the real world, by the way. 9=a^2+(2a)^2 9=a^2+4a^2 9=5a^2 9/5=a^2 SQRT(9/5)=a Enjoy 
Gah, OK, thanks. :p

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