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what about crank arm flex? and wheel flex? those could be parts of the flex equation also.
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Originally Posted by maddog17
(Post 6302460)
what about crank arm flex? and wheel flex? those could be parts of the flex equation also.
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Originally Posted by kensuf
(Post 6308799)
Wheel flex definitely. I've got a set of ksyrium elite's that just haven't been "right" since a guy stuck a foot in them during a crit last year, and they now flex quite a bit and I lose a lot of power. I had a set of custom wheels built up for myself for Christmas and the difference is night and day.
Crankarm, seatpost, and handle bar flex are all also going to return any flex to the system. No losses. |
Faster in an actual race? I would think so because of cornering. Also, wouldn't flexing metal parts (rims/frame) lose at least SOME energy due to heat? There is some friction there, even if it's negligible.
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Think of it this way.
If you had to lift a weight using a pulley system twice, once with a super strong chain, the second time with a flexible peice of nylon, you will have a harder time lifting it with the nylon because you "wasting" energy on stretching the nylon. So yes, stiffer frames are faster. Assuming all things equal you will probably gain a tiny amount of performance. Not noticeable of course. Next topic. |
Originally Posted by jeffreyahorn
(Post 3612781)
Comes back in what direction? If the frame flexes perpendicular to the direction of motion, the "spring" back would then also be perpendicular (180 degrees from initial flex) to the intended acceleration (straight ahead). A flexing frame has created two vectors of acceleration: 1) the intended forward direction, 2) a vector in the direction of the flex. As such, the energy that is transferred to flex the frame is at the expense of the total energy that was produced for forward motion.
JAH (Physics and Chemistry degrees) |
I sure don't.
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Originally Posted by Amen
(Post 6612674)
Think of it this way.
If you had to lift a weight using a pulley system twice, once with a super strong chain, the second time with a flexible peice of nylon, you will have a harder time lifting it with the nylon because you "wasting" energy on stretching the nylon. So yes, stiffer frames are faster. Assuming all things equal you will probably gain a tiny amount of performance. Not noticeable of course. Next topic. The only time anyone can say "next topic" is when they've built exact same dimensional bikes with greatly varied stiffness qualities and power testing is done at actual riding speeds and conditions. My thought is we would find stiffness numbers moot. |
Originally Posted by galen_52657
(Post 3614233)
Do the test on the trainer and check watts against heart rate. If frame flex is sapping power, the hear rate will be higher for the given power output. May have to do the test several times to average out factors like being tired, having a bad day at work, haven't gotten laid in a while...need to take a dump... you know...human factors...
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Originally Posted by waterrockets
(Post 4967775)
Here's how (and this is stated earlier in the thread): Put the bike in a trainer. Put a bucket under a forward pedal so you have about 1/2" of clearance beneath the pedal. Sit on the bike, lock the rear brake and apply force to the pedal until it rests on the bucket. Now, all the energy you have applied is stored in the frame, drivetrain, and wheel. Release the brake, and the pedal doesn't move, no energy is tranferred back to the cyclist, but the wheel will spin as all that energy is released directly into the trainer. Along these lines, I've heard it said (maybe by you?) that the flex will transfer back into the drivetrain if the frame returns to the '0' position before the flexing pedal reaches 6 0clock. Is this true? Has anyone seen video that would confirm that the frame rebounds by this time (or confirmed it with some other technique)? |
Boy, if someone would invent some type of theoretical boundary around the frame... and calculate the work in and work out...
Let me think... let me think... |
How did this get bumped?
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Originally Posted by ElJamoquio
(Post 6613556)
Boy, if someone would invent some type of theoretical boundary around the frame... and calculate the work in and work out...
Let me think... let me think... |
I gotta start looking at the dates before I start replying to posts.
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Originally Posted by Brian Ratliff
(Post 5021038)
Okay.
If that's the case, then there is no way I can see that the frame can return the energy back to the crank. But you're not, so it doesn't. Finite Element Analysis says that you're wrong - http://www.bikethink.com/Frameflex.htm Keith Bontrager's famous rant on frame flex says that you're wrong (look it up on the Internet Wayback machine - Trek had it pulled when they bought Bontrager) and so does David Kirk, who while not of Bontrager's legendary ability still seems to be pretty competent: http://www.kirkframeworks.com/Flex.htm It will deflect at the start of the power stroke until the force reached the peak, then it would return in proportion to the magnitude of the decreasing pedal force, but not give much of its energy back to the drivetrain because the spring force is returned during the part of the pedal stroke where it cannot very well help rotate the crank. |
no no no no no no no no no
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heh. The zombie thread.
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Lets stop reviving old threads. It's getting old... ha
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Hi
Did this test ever materialize, waterrockets? :D What is the latest on this subject? As I'm racing an old 531 steel frame now, I do not notice the frame being a limiting factor. It's stiff enough. I've raced carbon and alu and I enjoy steel more. Wondering if I should build the alu Cannondale frame that I have up on the wall but this thread reminded me of the crazy stiffness, I'm going to ride steel at least the rest of the year. I think frame stiffness is waaay overrated. I know stiff frames feel faster accelerating but that's mostly all it is, a feeling. |
Originally Posted by ratebeer
(Post 6613572)
How did this get bumped?
Originally Posted by Brian Ratliff
(Post 9652406)
heh. The zombie thread.
Originally Posted by frankum
(Post 9652712)
Lets stop reviving old threads. It's getting old... ha
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Originally Posted by Homebrew01
(Post 16804890)
:innocent:
I know but I just went through the whole thread and there was no conclusion on the subject! I want a conclusion! :D |
I, for one, think this topic is fascinating. I'm starting to think that neither thesis totally correct or incorrect.
I. If you follow the back trail through this thread (brings back memories, it does), you'll see mention of the "bucket test", which is basically a test where you put a pedal at 3 o'clock, put a bucket upside down underneath the pedal but not touching. If you stand on that pedal with the brakes engaged, you'll find the pedal will now deflect enough to touch the top of the bucket, and if you release the brakes at this point, you'll find the bike moves forward. A second version of this test is proposed in this thread where you place the pedals at 6 o'clock. Now if you stand on the pedal with the brakes engaged, and release the brakes, you don't get any movement. So, at the 3 o'clock crankarm position, deflecting the pedals results in energy releasing into the drivetrain. At 6 o'clock, it doesn't. II. Call a line connecting both hubs of the bike the "x axis", and a line vertical from the bottom bracket the "z axis". I think we can all agree that pedaling forces are primarily downward vectors along the z axis (pulling the pedal leads to almost nothing), and the bottom bracket is most susceptible to flex if the force applied to it is primarily in the downward direction, producing a twist in the bottom bracket around the x axis. One can see this easily on a trainer with a flexy frame. The frame will store energy much in the way of a spring. Force causes a proportional deflection. Energy is force integrated over a distance, meaning that energy is stored proportional the square of the deflection. Peak energy is stored at peak deflection, and as the force is reduced, the energy will reduce faster. For example, if you reduced the force causing the deflection by 1/2, the deflection will reduce by 1/2, and the energy stored will be reduced to 1/4 of the initial. This means, for all practical purposes, most of the energy transfer in and out of the frame will occur very close to the peak force. Most of the energy will be stored as the force is reaching its peak, and most of the energy will be released just after the force has reached its peak. I think we can also safely assume that damping in the frame is minimal (the frame doesn't appreciably heat up as you ride), and because there is a very large mass attached to this spring (your body), the frequency of the system will simply be the forcing frequency (your pedaling rpm). III. We have two boundary conditions, pedal at 3 o'clock (energy returned to drivetrain) and pedal at 6 o'clock (energy not returned to drivetrain). I think it is safe to assume that there is a continuity between these two points. For example, if the bucket test were done with the pedals at a position halfway between the 3 and 6 o'clock positions, half the energy would be returned to the drivetrain, half will not (in a static system, the energy remains stored; in a dynamic system, the energy goes into raising the mass of the foot/leg/body - since this occurs on the downstroke, the energy is simply lost). To me, this strongly indicates that for a person with a pedal stroke where max force is applied at the 3 o'clock pedal position, frame flex matters not at all. Energy is returned to the system as soon as it is diverted. The model for this would be moderate to hard steady efforts, seated in the saddle; like a time trial or steady climb. If, on the other hand, the maximum force is applied near or at the 6 o'clock position, the frame would divert that energy away from the drivetrain and put it into raising the body's gravitational center. The model for this would be pedaling from a standing position or a standing sprint. Depending on how much a person weighs, gearing, and her pedal stroke, the maximum force could well be at the bottom of the pedal stroke. In this case, a flexy frame diverts power from the drivetrain and doesn't give it back. Incidentally, because the CG of the body is raised by the energy release, it makes the bike feel "springy" or "whippy", like you are bouncing on a spring, which lends steel bikes their unique feel. The conclusion then, is flexy frames demand a smooth pedal stroke where maximum force is applied at or near the 3 o'clock pedal position and will work just fine for most riders. Most of cycling is done seated and at steady effort and a flexible frame does not penalize this. Flexy frames do, however, penalize anything done out of the saddle and where the maximum force is closer to the 6 o'clock position, which means it penalizes riders when they are search for absolute power regardless of efficiency. This makes a flexible frame bad for sport competition. Stiff frames avoid this power diversion altogether, which is why the sport bike market moves in this direction. TL;DR: Whether or not the system returns energy to the drivetrain depends on where the peak force is applied in the pedal stroke. if peak force is at the 3 o'clock pedal position (seated, steady pedaling), energy is returned; if peak force is at the 6 o'clock position (standing or choppy pedaling), energy is not returned. |
Energy can be stored in the flex or in the potential energy of lift the riders CG higher. The question is whether this stored energy is later returned usefully or dissopated through other mechanisms (damping being one possibility). You can bounce up and down in place on your legs or on a pogo stick and expend a lot of energy without going anywhere. Similarly you can expend a lot of energy accomplishing no useful work lifting weights at the gym or by flexing the springs in a Bowflex. With flex in a bike, some of the stored energy may be returned usefully but some is certainly lost.
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In Engineering we accept that a spring when used within its elastic range is 100% efficient. Elastic range means we do not disturb the atomic bonds and there is no permanent deformation. The force to compress a spring is linear to its change in length, meaning all the work as energy going into the spring is stored. It follows that when the force is removed from the spring, it returns all the energy stored as it decompresses.
A frame that deflects due to lack of stiffness, essentially behaves exactly the same as a spring. In practice, if a cyclist is exerting maximum force on the pedal at say 3 o'clock, the frame will absorb some of that work (energy) as it flexes, it will be lost to going through the chain to the back wheel. As the pedal stroke progresses though, at say somewhere between 5 and 9' O clock, the frame will lose its deflection and return to it's normal unstressed position. When that happens, it returns the work, or energy into the drive train. Another way to look at this is that even the stiffest frame on the market flexes, even if that flex is only a thousandth of an inch. It means all we have done, is increased the spring rate to a much stiffer spring, but it will still absorb and release the same energy. The fact that a spring is 100% efficient means there is no energy loss. There are practical limits though, on one of my old classic noodles, the back wheel loses traction from side to side under a full power sprint, which means energy is lost. Riding with a flat tire as posted above is different, as we are increasing rolling resistance exponentially and turning it into heat absorbed by the tire. Big energy loss. In short, fatter tubes save weight by producing the same strength with less material. I can remember way back never getting more than two seasons on a steel frame, before it cracks, somewhere. Do some research and see some folks with their light weight Trek's complaining about cracks. It is the strength that is important. |
Originally Posted by ColnagoC40
(Post 16805626)
...
A frame that deflects due to lack of stiffness, essentially behaves exactly the same as a spring. In practice, if a cyclist is exerting maximum force on the pedal at say 3 o'clock, the frame will absorb some of that work (energy) as it flexes, it will be lost to going through the chain to the back wheel. As the pedal stroke progresses though, at say somewhere between 5 and 9' O clock, the frame will lose its deflection and return to it's normal unstressed position. When that happens, it returns the work, or energy into the drive train..... Return flex from some directions could be transferred to muscle flex for instance. Wasted work. |
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