Kicking the bike backwards when standing... what's the cause?
Shifting ones weight forward? starting your stand with the pedal down (no force)?
/discuss |
Physics.
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Originally Posted by jmgorman
(Post 8336838)
Physics.
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If you have someone on your wheel, warn them you are about to stand.
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user error
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Originally Posted by jmgorman
(Post 8336838)
Physics.
Naaaaaahhh! http://snltranscripts.jt.org/77/pics/77rtheodoric6.jpg |
http://www.cosmosmagazine.com/files/...618_newton.jpg
I could tell you, but then I'd have to kill you. |
Originally Posted by wfrogge
(Post 8336777)
Shifting ones weight forward? starting your stand with the pedal down (no force)?
/discuss In the sense of center of mass (COM), if you're COM is moving up a steep hill at 10mph and you stand, you're probably moving 90% of the bike weight (your body) forward faster than 10mph, meaning the bike itself has to either slow down or go backwards (just for a moment). Now, I suppose you could apply sufficient force just as you started standing up that you keep things moving forward. Even if all the wheel does is slow down, someone close on your wheel could bump it. |
How do you counteract this mysterious and dangerous effect?
/discuss |
If it's gravity why does it happen on the flat too?
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Originally Posted by MONGO!
(Post 8337045)
If it's gravity why does it happen on the flat too?
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Originally Posted by SpongeDad
(Post 8337010)
In the sense of center of mass (COM), if you're COM is moving up a steep hill at 10mph and you stand, you're probably moving 90% of the bike weight (your body) forward faster than 10mph, meaning the bike itself has to either slow down or go backwards (just for a moment). Now, I suppose you could apply sufficient force just as you started standing up that you keep things moving forward.
Even if all the wheel does is slow down, someone close on your wheel could bump it. If you're another rider, your frame of reference is your own bike. When the guy in front stands up, his weight moves forward relative to his bike, but his COM continues at the same speed. Since the bike is lighter and the COM didn't move relatively, the bike moves closer to yours. The effect would be much smaller if we just rode much heavier bikes ;) |
Originally Posted by SilentShifter
(Post 8337041)
How do you counteract this mysterious and dangerous effect?
/discuss |
Originally Posted by bdcheung
(Post 8337104)
Because gravity doesn't go away when the road gradient is zero?
Originally Posted by nafun
(Post 8337180)
It's not so mysterious. When some people stand, the first thing they do is pull themselves forward off the saddle with their arms. When you do this, you are pulling the bike back by the handlebars. If the first thing you do is push hard on the pedals and let your legs raise you off the saddle, then the bike doesn't jump back.
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I didnt say it was mysterious..... just wanted a sanity check.
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Originally Posted by wfrogge
(Post 8337202)
I didnt say it was mysterious..... just wanted a sanity check.
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Magic
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Originally Posted by MONGO!
(Post 8337196)
So your saying the reason a bike moves "backwards" when a rider stands on flat ground is because gravity pulls it back?
In my previous post, I said the reason a bike moves backwards when a rider stands on flat ground is because of the law of reciprocal actions. |
it's basically the reverse of throwing your bike at the line. If there is someone on my wheel, I make an effort to stand smoothly and without throwing the bike backwards. It takes some effort.
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Originally Posted by bdcheung
(Post 8337274)
No, I was answering your question.
In my previous post, I said the reason a bike moves backwards when a rider stands on flat ground is because of the law of reciprocal actions. |
Originally Posted by MONGO!
(Post 8337320)
I don't see that post anywhere
or do I need to spell everything out? |
Originally Posted by bdcheung
(Post 8337104)
Because gravity doesn't go away when the road gradient is zero?
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Originally Posted by bdcheung
(Post 8337274)
No, I was answering your question.
In my previous post, I said the reason a bike moves backwards when a rider stands on flat ground is because of the law of reciprocal actions. |
Originally Posted by Phantoj
(Post 8337392)
It has nothing really to do with gravity.
Originally Posted by MONGO!
(Post 8337394)
You posted a picture of newton, you didn't specify if you were alluding to his 3rd law of motion or gravity.
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Originally Posted by nafun
(Post 8337180)
if the first thing you do is push hard on the pedals and let your legs raise you off the saddle, then the bike doesn't jump back.
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