Fixed. It did seem like a misunderstanding from the beginning. So it seems that we're in agreement that an 8" rotor, while undoubtedly a bad idea, is probably not a drastic increase in quick release ejection force over, say, a 140 that I've been running for years?

No. The force is, in fact, exactly the same, as long as the rate of deceleration is the same. The direction and curvature of the force is different, though. And there's another "but", to which I'll get back in a second.

I'm still on the edge of my seat here!

In related news, I am picking up the fork from the powdercoater now, so it looks like by tomorrow afternoon I will have a real-world "did it explode?" report.

The force required out of an 8" rotor, or a 140 for that matter, to pull from the dropouts is WAY more than the force required to send you over the bars.

You'll go OTB years before you'll pull a disc equipped front wheel out of the dropouts.

Sorry elemental, I got distracted. So what I wanted to say is, a larger rotor will offer a larger counter-torque during deceleration for equal attrition force applied at the edge of the rotor by the pads. In case of a sudden (emergency) stop, a cyclist would apply all the force he can muster, on the brake lever, and in the case of a larger rotor, that will mean a quicker deceleration, therefore, a larger force exerted by the spindle of the wheel in the drop-outs.