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Old 12-20-12 | 11:58 PM
  #15  
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Fat Boy
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Originally Posted by echappist
Also, what about savings at 20 and 25mph? i know there's a equation, and it's somewhat linear w.r.t. to ground speed (or is it)
Drag is just a squared function. Nothing tricky. Mr. Bernoulli said so.

x = speed of interest (mph)
Dx = Power at speed of interest (grams)
D30 = Power at 30mph (grams)

Dx = D30 * (x^2/900) (FWIW, 900=30^2)

also:
x = speed of interest (mph)
Px = Power at speed of interest (watt)
P30 = Power at 30mph (watt)

Px = P30 * (x^3/27000) (FWIW, 27000=30^3)


This will give you the aero side of the equation. There will be a rolling resistance component as well. My guess is that as speed goes up, the rolling resistance gets kind of overpowered by aero, but that's just speculation.

Last edited by Fat Boy; 12-21-12 at 12:54 PM. Reason: Changed due to WR pointing out I was screwed up.
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