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Old 10-21-05 | 08:55 PM
  #24  
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rickkko
TREK 2300 owner
 
Joined: Jul 2005
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From: Sandy Eggo CA

Bikes: '04 Trek 2300, '77 Panasonic Touring Deluxe

Originally Posted by luv2climb
You are correct that 100% grade is eqaul to a 45 degree hill. Here is the formula:

grade = vertical_climb / horizontal_distance

where both vertical_climb and horizontal_distance are both converted to the same measurement units. So if a hill goes up 264 feet in 2 miles, then we can first convert 2 miles to 10560 feet -- so the grade is then 0.025 = 264 feet / 10560 feet, which is 2.5%

Thus a 45 degree hill is one that for each 1 foot horizontally you travel you go up vertically one foot or

1 ft / 1ft = 1.00 or 100%

Hope that helps everyone.
How do you compensate for zig-zagging back and forth as seen in picture below?

Of course its still the same grade, ya' just cover a lot more distance traversing back and forth and effectively only encounter the full effect of the grade when you turn at the end of each traverse.

..rickko..
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