Originally Posted by
cyccommute
I won't quote the whole page but he goes through the calculations for determining the deceleration on a specific bike and rider. At the end of the discussion he say:
Bicycling Science, 3rd edition, David Gordon Wilson, 2004, p245. Here's a (very) crude reproduction of his figure
As you can see "point 3" is over the front wheel. "Moments of torque around..." implies rotation about that point, not simply lifting the rear wheel. Simply lifting the rear wheel isn't "going over the handlebars". His language is very clear.
Again, you have provided your interpretation of the text (or a figure in the text), and you obviously misunderstand the text.
When the rear wheel is lifted, the rider has begun going over the handlebars. If nothing changes (rider keeps the brakes on with the same force) then he will continue rotating around the front wheel. The diagram you created does not show the centre of mass over the front wheel, just the point about whicht he rider and bike are rotating, and that point is the same regardless of how far the rear wheel is lifted.
THe problem with your understanding is that deceleration when the centre of mass is over the front wheel is impossible. The maximum theoretical deceleration when balanced n a nose wheelie is
zero. In order to stop from rolling forward in a nose wheelie the rider must shift his weight and rotate slightly back. Your failure to understand this indicates a major and disturbing misunderstanding of physical systems in motion.