You interpret it as already having the wheel as far from the ground as possible. I think at that point you are pretty far into your journey over the bars. I interpret it as applying so much front brake that your rear wheel has begun to lift, and barring any change, will continue to lift until you have gone around the handlebar. The diagram you posted showed a bike sitting on level ground, but rotation around the front wheel, any amount, is a part of `going over the handlebars. We just generally release the brake when we get to that point.


First, a nose wheelie can be done in motion - you don`t have to have stopped. Secondly, zero velocity does not equal maximum deceleration. This is another indication of your lack of understanding of mechanical systems. I can`t teach you that here, you need to take grad 11 physics again.


This statement is exactly how I know you (or the author) are wrong - the maximum theoretical deceleration when over the handlebars is zero. When the centre of mass is behind the front wheel, gravity wants to pull the rear wheel back to the ground, but deceleration makes the rear wheel want to go forward and up. These two forces working against eachother are what makes braking possible when the centre of mass is behind the front wheel. If the centre of mass is directly over the front wheel, gravity is not pulling the rear wheel back to the ground, but it pulling it directly toward the pivot point which does not affect the movement one way or the other, and so the forward rotational force caused by braking has nothing to counter it, so no deceleration is possible. The theoretical maximum deceleration is zero. The practical deceleration is slightly higher than zero as the rider can scoot his weight back a bit before braking, but this eliminates the weight-over-the-front-wheel scenario.