Originally Posted by OldTryGuy

Short when wind is at one's back and longer when riding into the wind.

Just like the old high school math problem "Fred pedals into the wind at 10 mph for 20 miles. How fast does he need to pedal on the return trip (with tailwind) to average 15 mph?"

I've forgotten how to solve it, or is it?: (20 miles/10 mph +10 miles/x) = 40 miles/15 mph (solve for x):

Regardless, it's very windy here today and I'm hitting the gym cardio machines instead, with the hopes of bike friendlier riding weather tomorrow.