Originally Posted by Doge

The pneumatic part is a spring for this. And yes to your assumption.

I calculated - non-differential equation from the start of the deformation to the end of cycle time as being 1ms. That was algebra and arithmetic. The deformation part is actually .5ms as the rubber contacts the road until it is fully deformed. that is not much time to get full drop.

Do you, @wphamilton, think in .5ms all tires deform (drop) as much as they would at rest?

If not, do you agree the contact area's will be different?