The equation from Talbot is
Y= R * tan((90deg - head angle)/2)
where Y is the fork offset or rake (inches), and R is the wheel radius in inches. If your head angle, radius, and for offset satisfy this condition, you have "Neutral Steering."
So for my 1952 Rudge the wheel is 347 millimeters and the head angle is 73. My offset for neutral steer is 2.04 inches. However, the Raleigh spec for the bike says the offset is 2.5", which according to the Talbot book means my bike is "slower than neutral." I am not sure what neutral means.
I can calculate the trail for this bike, to be 39.7 mm. I can also calc the trail if it satisfied the neutral condition of Y=2.04". That would be 51.9 mm. So "less neutral" or "quicker than neutral" correlates to less trail. What else does it mean? I don't know.
While these discussions seem to offer insight, if what the terms mean is not agreed to by the participants, I can't see where my intent to help anyong else can possible be effective. If we ever do stop talking in circles, we will never know it.
It's seems that whatever Talbot was trying to say has no connection to what we here on BF are trying to say.