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Old 08-15-24 | 11:07 AM
  #36  
alpineboard
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Joined: Jul 2024
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Let us agree on a few things, one complete revolution of the rim equals one complete revolution of the tire.
If you cut the tire circle at one point and lay it flat on the ground in a straight line, like a belt, one complete revolution of the circle equals
one full length of this belt, this does not change, ever, squish or no squish. This distance does not change if it gets squished under load or no squish under no load.
One rev of the wheel equals one circumference distance. Assume there is not any slip during squish load footprint.
I fully realize there other variables going on, at the squish load spot, compression, temperature, ect, but all these are irrelevant
until the understanding of the belt theory is understood. Am def willing and able to hear all opinions about this subject.
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