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Old 08-15-24 | 11:11 AM
  #37  
njkayaker
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From: Far beyond the pale horizon.
Originally Posted by tomato coupe
With that definition, your theory is incorrect. The effective radius of the tire is larger than what you're calling the "patch" radius, and it is related to the tire circumference (or roll-out) by the familiar L = 2 * pi * radius.

Unloaded radius > effective radius > loaded (patch) radius
I said this multiple times! The illustration clearly shows it!

Originally Posted by tomato coupe
Unloaded radius > effective radius > loaded (patch) radius
Your "effective radius" isn't clear. (The actual effective radius is the patch radius.)

I suspect it's more like:

"Tire radius (loaded) approximately equal to tire-radius (loaded) > loaded (patch) radius."

(But we don't care about either tire radius. We only care about the patch radius.)

Last edited by njkayaker; 08-15-24 at 11:57 AM.
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