Originally Posted by unkchunk
How far down stream a swimmer would end up when swimming at a speed of 2 mph in a 3 mph current in a mile wide section of a river.
Off the top of my head...a^2 + b^2 = c^2
a= 1
b=x
c=1.5
1^2 + x^2 = 1.5^2 => x^2 = 2.25 - 1 => x = Sqrt(1.25)
So our simmer would end up about 1.118 miles downstream?