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Old 02-15-07, 02:51 PM
  #37  
dalmore
Neat - w/ ice on the side
 
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ok I guess I see what you are saying on this point ... For the sake of clarity say I'm averaging a constant speed of 20 mph by bouncing between 21 and 19 mph. You are saying that the rotational energy change when dropping from 21 mph to 19mph is equal to the rotational energy change of going back from 19 to 21 so it's a net zero game. ok, I can swallow that.

BUT that is not to say that I agree that rotating mass is the same as non rotating mass except when accelerating. Only that I don't have the math skills to argue the point.
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