Originally Posted by Shiznaz
What is a problem is that my camera has a 4.5V proprietary DC input. If I get around the proprietary input and run 5V into the camera will I fry it? Otherwise I will have to carry an external battery charger for the camera along with an extension lead since it doesn't have a folding built in plug and kind of ruins the perfection of my charging setup!
You camera has a proprietary battery? Hrmm.... A quick online search found a few similar questions to yours but no "Yes I did it and it worked" answers...
You could try making a simple voltage divider using two resistors in series and tapping off from around one resistor. If you were to tap around R1 the voltage drop around R1 would be
V_R1 = (R1/(R1+R2))*input voltage
So you'd want a resistor combo that gave you 4.5V=(R1/(R1+R2))*5V
Note that I have absolutely no idea what I'm doing... I'd definitely test this with a meter to make sure you're getting the voltage you want and enough current.