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Old 07-06-08 | 02:42 AM
  #33  
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DannoXYZ
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Joined: Jul 2005
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From: Mesa, AZ

Bikes: Moots RCS, tandem, beach-cruiser, MTB, Specialized-Allez road-bike, custom track-bike

In reference to this picture, you need to actually use an integration from 0-5.58kgm of torque to find out the exact twist-angle.

http://www.bikeforums.net/attachment...1&d=1215283027

where actual increase in TENSION = TORQUE/LEVER * SIN(X)

The tension on a tangential 90-degree spoke ALL goes into stretching the spoke. On a 0-degree radial spoke, none of the initial tension goes into the spoke (like pushing sideways object hanging on a rope). All of the torque goes into twisting the hub. YOU Can test this by twisting a hub with very loose spokes. You'll find that ALL of your hand's torque goes into twisting the hub, and you can twist it quite a bit, but none of that force goes into stretching any of the spokes. As the angle increases more and more, more of the torque goes into stretching the spoke. At some point where the stretch balances the applied torque, the hub stops twisting.

If you add Young's Modulus and the cross-section of the spoke to the above equation and integrate from 0-5.58kgm torque, you can determine the exact amount of tension, resultant stretch and angle of wind-up.

Last edited by DannoXYZ; 07-06-08 at 02:46 AM.
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