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Replacing Axle
Got a new fork for my road bike, happens to be a track fork with a narrower dropout. The axle I have (approximately 9.5mm) is just slightly too large for the dropouts. I have looked online for a slightly smaller axle but all I have come up with are skewers, apparently around 5mm. I haven't used a skewer before but it looks like it may come with a hollow threaded axle. Anyone know the circumference of a hollow threaded axle that might come with a skewer? Sources for purchasing skewers or axles? Do they generally come with caps/bearings/locknuts that would fit the hub such as what was on the 9.5mm axle and the hub? Comparative experiences? Thank you and happy holidays.
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If the diameter is 9.5 mm , what is its circumference is that your math quiz? :rolleyes:
online is a crapshoot if you dont really know what you need , specifically, .. rather than approximate. since you dont how, How about patronizing a Local brick and mortar Bike Shop? show them what I cannot see. |
Normally front axles for cup and cone bearing assemblies are 9.0 mm. Those can be either drilled through for a quick release skewer or not.
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I think we got bigger issues here; no front brake drilling; proper rake; crown height.
I wouldn't be throwing a track fork on a road bike without considering those issues. |
Originally Posted by rpenmanparker
(Post 18414197)
Normally front axles for cup and cone bearing assemblies are 9.0 mm. Those can be either drilled through for a quick release skewer or not.
Note that you'll need a front quick release skewer to complete the conversion. |
I'd assume the front wheel is worth $50 new so might as well buy another cheap front wheel that fits.
But I also thought road and track bikes both had 100mm front spacing |
Closing this as a duplicate of this thread: http://www.bikeforums.net/bicycle-me...cing-axle.html
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