Got a new fork for my road bike, happens to be a track fork with a narrower dropout. The axle I have (approximately 9.5mm) is just slightly too large for the dropouts. I have looked online for a slightly smaller axle but all I have come up with are skewers, apparently around 5mm. I haven't used a skewer before but it looks like it may come with a hollow threaded axle. Anyone know the circumference of a hollow threaded axle that might come with a skewer? Sources for purchasing skewers or axles? Do they generally come with caps/bearings/locknuts that would fit the hub such as what was on the 9.5mm axle and the hub? Comparative experiences? Thank you and happy holidays.

If the diameter is 9.5 mm , what is its circumference is that your math quiz?


online is a crapshoot if you dont really know what you need , specifically, .. rather than approximate.

since you dont how, How about patronizing a Local brick and mortar Bike Shop? show them what I cannot see.

Normally front axles for cup and cone bearing assemblies are 9.0 mm. Those can be either drilled through for a quick release skewer or not.

I think we got bigger issues here; no front brake drilling; proper rake; crown height.

I wouldn't be throwing a track fork on a road bike without considering those issues.

More than likely, he currently has a nutted axle. A lot of cheaper bikes have 3/8" (9.5mm) nutted axles. Swapping an axle out on one of these bikes would require new cones as well because the 3/8" threaded cones will not fit a 9mm axle. It can be done, though, with the right parts. An option for the conversion is available here: Wheel Master Threaded Quick Release Axle - FT, 9 x 1 x 100 x 108

Note that you'll need a front quick release skewer to complete the conversion.

I'd assume the front wheel is worth $50 new so might as well buy another cheap front wheel that fits.

But I also thought road and track bikes both had 100mm front spacing

Closing this as a duplicate of this thread: https://www.bikeforums.net/bicycle-me...cing-axle.html