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BTW I love how the pictures being used are illustrating clearly the point that the tires are not pointed into the turn.
How can I tell? Look at the rider's head. The rider is looking into the turn. Does the wheel line up with the rider's head? The answer is clearly no in the pictures below:
Originally Posted by cyccommute
(Post 8977489)
http://images.google.com/url?source=...ks8fnYECDn6yQA
http://farm4.static.flickr.com/3268/...55abe9.jpg?v=0 http://farm4.static.flickr.com/3044/...6148cd.jpg?v=0
Originally Posted by cyccommute
(Post 8980004)
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Originally Posted by msincredible
(Post 8983401)
BTW I love how the pictures being used are illustrating clearly the point that the tires are not pointed into the turn.
How can I tell? Look at the rider's head. The rider is looking into the turn. Does the wheel line up with the rider's head? The answer is clearly no in the pictures below: |
Originally Posted by DannoXYZ
(Post 8958904)
To understand countersteering and getting used to it so that it's 2nd-nature, practic in big parking lots. Get up to 5mph+ and ride with your hands lightly on the handlebar. Let go of one hand (let's say left) while keeping the other one near, stay in a straight line. Now, with right hand, push on the bar so that it turns the bar left. Which way does the bike lean and which way does it turn?
Now do the opposite, pull on the bars so that it turns the bar right (not as easy to do). Which way do you lean and which way does the bike turn? Repeat with only the left hand on the bar, push on it, pull on it and see which way the bike leans and turns. What happens on the bike a lot of times is that both hands ends up pushing and they fight each other and you end up going straight instead of turning. Or you try to consciously turn the handlebars in the direction you want to go and the bike refuses to respond that way. It's pretty simple physics if you imagine looking down on the rider from above. The front & rear contacts patches are inline with the centre-of-gravity in between. Which way does the front-contact patch move when you steer left? Steer right? That explains why the bike leans to the other side and you turn to that side. I did this for a bit and it blew my mind!!! just not quite what i expected. anyone reading this thread, just do this and you'll figure it out. |
Originally Posted by msincredible
(Post 8983401)
BTW I love how the pictures being used are illustrating clearly the point that the tires are not pointed into the turn.
How can I tell? Look at the rider's head. The rider is looking into the turn. Does the wheel line up with the rider's head? The answer is clearly no in the pictures below: |
Originally Posted by DannoXYZ
(Post 8981464)
There you go again. WikiPedia is NOT a credible source. It's not an admissible reference for high-school papers, much less university/phD level dissertations. Where is a sideways force coming from? The only forces on a moving bike is longitudinal. Friction pushes you back and your momentum pushes you forward. Where does the sideways force come from and what generates it?
Let me give you a hint, for any given lean-angle, there are three states. There is a "balanced" radius of turn and speed such that no steering is needed. There is also a radius & speed where you need to "turn into" the turn and there's a radius & speed where you need to "turn out" of the turn. Since there are three variables, we have a cartesian-product of 9 possible states of cornering to describe. Look up camber thrust and camber roll as it relates to rounded tyre profiles. You have been shown numerous examples of bicycle wheels turn into the corner of a curve. You have been shown explanations for the centripetal force acting on a bicycle wheel. You asked, and I explained, how you can ride a bike while leaned in a straight line. In the face of all that you still contend...as do others...that the wheel of a bicycle is pointed away from the turn during cornering. It is up to you, now, to show how centripetal force works opposite the direction of a turn. I'd like illustration, pictures, etc. of a bicycle that clearly the wheel to the opposite side of the centerline of the bicycle. The picture also has to be of a bicycle clearly in control without the rear wheel sliding to the outside of the curve. I look forward to your proving that centripetal motion and centripetal force don't work the way that it's been taught in physics classes for eons. Edit: Camber thrust? The friction of the tire pulling the bicycle around the corner? How is that any different from what I have described? It doesn't appear to me to say anything about the bicycle being steered in a direction opposite to the direction of travel. It simply makes the bike not go off in a tangent to the curve. In other words, it still centripetal force acting on the tire. The curvature of the tire helps pull the bicycle around the corner. So another thing you need to show. How does this make you steer opposite the direction of the curve? Or is this just a red herring? Here's a little light reading. Look at page 13 in particular. First paragraph. "...To stay balanced, the handlebar's angle of rotation will deviate from zero depending on the radius of the curve and the velocity [of the vehicle]." With an illustration that clearly shows the handlebar's deviation from zero in the direction of the curve. Just like the computer animation I linked to. |
Wiki still rocks - there are references and terms; it is a starting point.
I'm sorry, did someone cite their thesis in this thread? ...must'a missed it. From there, I go out and see (uhm, saw) for myself, starting out with walking around the driveway with one of my bikes. Tonight is the local crit, where I test my OWN conclusions - from there, that's it, for me. |
I'm resurrecting this... try this for a test.
Put both hands right next to your stem (one on each side of course). Ride. See which side you push on to go in each direction. You'll find you'll push forward on your right side to go right. Push forward on the left side and you'll go left. Now do that on a descent around a curve. The more you push right, the sharper you will turn to the right. (and vice-versa on the left) |
^^^^^
Exactly. With the hands in the hooks, you'll find that turning to the right can be done with only the right hand, in a open position, where it can't be used to pull on the bars. There is never a need to pull on the bars or push with the left hand. Just vary the countersteering pressure and the bike will go from leaned over and turning sharply, or back to upright if no pressure is applied. Use the left hand for left hand turns. |
seeing the pictures above, i made a conscious effort today to turn the head and also the shoulders into the turn on a particular curve where before if i didn't slow down i would swing wide into the middle of the road. i also leaned my body in line with the tilt of the bike rather than staying more upright than the bike.
result was whooooooshhhhh. very tight turn at higher than normal speed. |
^^^^
Leaning with the bike should be the natural thing to do. Leaning away from the turn makes no sense. The bike isn't going to fall over. I still have to emphasize countersteering. It takes little effort on a bicycle compared to a motorcycle, but the principle is still the same. Learn to countsteer and you won't swing wide. If you do, at least you then know how to correct the problem. I still say that most cyclists would benefit greatly from an introductory motorcycle course. They don't cost that much. http://www.msf-usa.org/ |
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