Graphene.
10-06-10 | 11:20 AM
#26
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10-06-10 | 11:24 AM
#27
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Graphene has been available for a while now in raw thick sheets -- they use it in automotive racing for splitters because it can take a beating and is fairly cheap. It's not as strong as carbon fiber currently in commercially available sheet form, but it's also much cheaper than carbon fiber.
I imagine this is the same tech applied at a nano level.
I imagine this is the same tech applied at a nano level.
10-06-10 | 12:07 PM
#28
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But then again, what do I know.
10-06-10 | 12:13 PM
#29
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10-06-10 | 12:18 PM
#30
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Graphene has been available for a while now in raw thick sheets -- they use it in automotive racing for splitters because it can take a beating and is fairly cheap. It's not as strong as carbon fiber currently in commercially available sheet form, but it's also much cheaper than carbon fiber.
I imagine this is the same tech applied at a nano level.
I imagine this is the same tech applied at a nano level.
And there is a huge difference between a continual sheet of graphine, which is very strong, and graphite, composed of many, many small 'sheets'.
It was just last year that the first graphine sheet larger than 1000 square micrometers was produced.
Here is an article on attempts to use larger sheets for touch screens: https://www.newscientist.com/article/...ene-sheet.html
Last edited by Nerull; 10-06-10 at 12:26 PM.
10-06-10 | 12:24 PM
#32
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The electrical properties of graphene can be described by a conventional tight-binding model; in this model the energy of the electrons with wavenumber k is[53][55]
with the nearest-neighbor hopping energy γ0 ≈ 2.8 eV and the lattice constant a ≈ 2.46 Å. Conduction and valence band, respectively, correspond to the different signs in the above dispersion relation; they touch each other in six points, the "K-values". However, only two of these six points are independent, whereas the rest is equivalent by symmetry. In the vicinity of the K-points the energy depends linearly on the wavenumber, similar to a relativistic particle. Since an elementary cell of the lattice has a basis of two atoms, the wave function even has an effective 2-spinor structure. As a consequence, at low energies, even neglecting the true spin, the electrons can be described by an equation which is formally equivalent to the massless Dirac equation. Moreover, in the present case this pseudo-relativistic description is restricted to the chiral limit, i.e., to vanishing rest mass M0, which leads to interesting additional features:[55]
Here vF ~ 106 is the Fermi velocity in graphene which replaces the velocity of light in the Dirac theory; 
is the vector of the Pauli matrices, 
is the two-component wave function of the electrons, and E is their energy.[80]
with the nearest-neighbor hopping energy γ0 ≈ 2.8 eV and the lattice constant a ≈ 2.46 Å. Conduction and valence band, respectively, correspond to the different signs in the above dispersion relation; they touch each other in six points, the "K-values". However, only two of these six points are independent, whereas the rest is equivalent by symmetry. In the vicinity of the K-points the energy depends linearly on the wavenumber, similar to a relativistic particle. Since an elementary cell of the lattice has a basis of two atoms, the wave function even has an effective 2-spinor structure. As a consequence, at low energies, even neglecting the true spin, the electrons can be described by an equation which is formally equivalent to the massless Dirac equation. Moreover, in the present case this pseudo-relativistic description is restricted to the chiral limit, i.e., to vanishing rest mass M0, which leads to interesting additional features:[55]Here vF ~ 106 is the Fermi velocity in graphene which replaces the velocity of light in the Dirac theory; is the vector of the Pauli matrices, is the two-component wave function of the electrons, and E is their energy.[80]
10-06-10 | 12:32 PM
#33
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^^^^ which means...?
Imagine that post being spoken by Data in a scene in Star Trek TNG. Capt Picard gives him a blank stare. How does Data explain it in one sentence in his next line?
Imagine that post being spoken by Data in a scene in Star Trek TNG. Capt Picard gives him a blank stare. How does Data explain it in one sentence in his next line?
10-06-10 | 12:43 PM
#36
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10-06-10 | 12:44 PM
#37
Bike ≠ Car ≠ Ped.
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Bikes: Some bikes. Hell, they're all the same, ain't they?
It means he copied and paste the Wikipedia entry word for word. Yay plagiarism!
link
link
I wanted to see if he knew what he was copying.
10-06-10 | 12:45 PM
#38
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It means he copied and paste the Wikipedia entry word for word. Yay plagiarism!
link
link
It's only a violation of the copyright if he failed to attribute (which he did). And it's not plagiarism because he in no way tried to claim it was his work. Any idiot can tell he copied and pasted that (the hyperlinks are a dead giveaway).
10-06-10 | 12:56 PM
#39
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10-06-10 | 07:53 PM
#42
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From: The Path to Fredvana
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https://en.wikipedia.org/wiki/Wikiped...ported_License
It's only a violation of the copyright if he failed to attribute (which he did). And it's not plagiarism because he in no way tried to claim it was his work. Any idiot can tell he copied and pasted that (the hyperlinks are a dead giveaway).
It's only a violation of the copyright if he failed to attribute (which he did). And it's not plagiarism because he in no way tried to claim it was his work. Any idiot can tell he copied and pasted that (the hyperlinks are a dead giveaway).
That said, it's an internet forum, not an academic journal. I don't want to make a big deal out of it.
Last edited by z90; 10-06-10 at 08:49 PM.
10-06-10 | 08:05 PM
#43
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The electrical properties of graphene can be described by a conventional tight-binding model; in this model the energy of the electrons with wavenumber k is[53][55]
with the nearest-neighbor hopping energy γ0 ≈ 2.8 eV and the lattice constant a ≈ 2.46 Å. Conduction and valence band, respectively, correspond to the different signs in the above dispersion relation; they touch each other in six points, the "K-values". However, only two of these six points are independent, whereas the rest is equivalent by symmetry. In the vicinity of the K-points the energy depends linearly on the wavenumber, similar to a relativistic particle. Since an elementary cell of the lattice has a basis of two atoms, the wave function even has an effective 2-spinor structure. As a consequence, at low energies, even neglecting the true spin, the electrons can be described by an equation which is formally equivalent to the massless Dirac equation. Moreover, in the present case this pseudo-relativistic description is restricted to the chiral limit, i.e., to vanishing rest mass M0, which leads to interesting additional features:[55]
Here vF ~ 106 is the Fermi velocity in graphene which replaces the velocity of light in the Dirac theory; is the vector of the Pauli matrices, is the two-component wave function of the electrons, and E is their energy.[80]
with the nearest-neighbor hopping energy γ0 ≈ 2.8 eV and the lattice constant a ≈ 2.46 Å. Conduction and valence band, respectively, correspond to the different signs in the above dispersion relation; they touch each other in six points, the "K-values". However, only two of these six points are independent, whereas the rest is equivalent by symmetry. In the vicinity of the K-points the energy depends linearly on the wavenumber, similar to a relativistic particle. Since an elementary cell of the lattice has a basis of two atoms, the wave function even has an effective 2-spinor structure. As a consequence, at low energies, even neglecting the true spin, the electrons can be described by an equation which is formally equivalent to the massless Dirac equation. Moreover, in the present case this pseudo-relativistic description is restricted to the chiral limit, i.e., to vanishing rest mass M0, which leads to interesting additional features:[55]Here vF ~ 106 is the Fermi velocity in graphene which replaces the velocity of light in the Dirac theory; is the vector of the Pauli matrices, is the two-component wave function of the electrons, and E is their energy.[80]
10-07-10 | 09:58 AM
#46
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From: Boston
It doesn't have to be a violation of copyright to be plagiarism, and he didn't attempt to attribute it at all. I was being a bit flip, but when you copy something, even in an informal discussion on a board, I think you should clearly state where it came from. And the fact that it's obvious plagiarism doesn't somehow make it not plagiarism.
That said, it's an internet forum, not an academic journal. I don't want to make a big deal out of it.
That said, it's an internet forum, not an academic journal. I don't want to make a big deal out of it.
I'm not trying to make a big deal of this either, I just want to explain why I don't believe it's plagiarism which I think is a very serious charge that should be reserved for times when it actually matters. It was a copyright violation, although all he had to do to fix that was attribute it since the original material is CC share alike.
10-07-10 | 10:47 AM
#47
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Points taken. My post was certainly not meant as a "very serious charge", and I doubt anyone took it that way. It was meant to be a bit of a barb, because I think it's slack just to dump a bunch of text in from an unnamed source and post it without attribution.
I do think the analogy of internet forum = casual conversation fails in this case. In a casual conversation, you can't suddenly start spouting word for word from an undocumented source unless you have some kind of freak photographic memory.
I stand by my larger point, which is you should include attribution when posting large chunks of material from outside sources, even if it's just starting your post with "From Wikipedia", and then putting quotes around the block of text.
There are many different views on plagiarism, though, and intelligent people can disagree.
And now, for you entertainment
Tom Lehrer's musical take on the topic of plagerism
I do think the analogy of internet forum = casual conversation fails in this case. In a casual conversation, you can't suddenly start spouting word for word from an undocumented source unless you have some kind of freak photographic memory.
I stand by my larger point, which is you should include attribution when posting large chunks of material from outside sources, even if it's just starting your post with "From Wikipedia", and then putting quotes around the block of text.
There are many different views on plagiarism, though, and intelligent people can disagree.
And now, for you entertainment
Tom Lehrer's musical take on the topic of plagerism
Last edited by z90; 10-07-10 at 12:07 PM.
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