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Old 02-05-12 | 01:54 PM
  #5  
asgelle
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Joined: Apr 2006
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From: Albuquerque, NM
Originally Posted by billydonn
How can you have two rides of equal duration (50 minutes), both indoors on a trainer using the exact same equipment, where you go farther (i.e. faster) on one, yet produce fewer Kilojoules (i.e. less work)? Here are the particulars:

Jan 24- 12.8 miles, Avg power 127, Normalized power 165.... 413 Kj
Feb 2- 13.3 miles, Avg power 136, Normalized power 149.... 408 Kj
Work (J) equals power (W) times time (s). It doesn't matter how the power was applied; total work is the integral of instantaneous power over the duration of exercise (i.e., linear). For the two cases, 127 W over 49:56 (2996 seconds) is 380.5 kJ. 136 W gives 408 kJ.

So the question is where did your 413 kJ number come from?
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