Power Meter Puzzler
#1
Thread Starter
Council of the Elders
Joined: Jul 2008
Posts: 3,759
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From: Omaha, NE
Bikes: 1990 Schwinn Crosscut, 5 Lemonds
Power Meter Puzzler
How can you have two rides of equal duration (50 minutes), both indoors on a trainer using the exact same equipment, where you go farther (i.e. faster) on one, yet produce fewer Kilojoules (i.e. less work)? Here are the particulars:
Jan 24- 12.8 miles, Avg power 127, Normalized power 165.... 413 Kj
Feb 2- 13.3 miles, Avg power 136, Normalized power 149.... 408 Kj
Jan 24 ride was a series of 1-minute intervals
Feb 2 ride was a set of 5 minute intervals.

Perhaps I do not understand Kilojoules... can someone please clarify?
Jan 24- 12.8 miles, Avg power 127, Normalized power 165.... 413 Kj
Feb 2- 13.3 miles, Avg power 136, Normalized power 149.... 408 Kj
Jan 24 ride was a series of 1-minute intervals
Feb 2 ride was a set of 5 minute intervals.
Perhaps I do not understand Kilojoules... can someone please clarify?
#2
Stratiotika ktemata
Joined: Aug 2006
Posts: 286
Likes: 1
From: Vero Beach, FL
Possible explanation #1: power and effort do not increase in a linear fashion, so doing those 1 minute power intervals averages out a little higher.
Possible explanation #2: those numbers are well within the margin of error.
Possible explanation #2: those numbers are well within the margin of error.
#3
Senior Member


Joined: Jun 2008
Posts: 9,201
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From: Vancouver, BC
This. Most trainers are designed to simulate outdoor riding so resistance increases with the square of speed. Putting out 30% extra power will only give you a 10% increase in speed.
#4
Senior Member


Joined: Jun 2010
Posts: 1,055
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From: Riverside, CA
Bikes: Lynskey R230 DA DI2 ENVE 3.4 SES, 6KU Fixie, Cheap Aluminum Slapstick Trainer only bike
Or in another way of saying... your burnt energy vs. work performed is not linear depending on level of effort. (Guess that's why you train for efficiency on certain discipline).
#5
Senior Member

Joined: Apr 2006
Posts: 4,608
Likes: 506
From: Albuquerque, NM
How can you have two rides of equal duration (50 minutes), both indoors on a trainer using the exact same equipment, where you go farther (i.e. faster) on one, yet produce fewer Kilojoules (i.e. less work)? Here are the particulars:
Jan 24- 12.8 miles, Avg power 127, Normalized power 165.... 413 Kj
Feb 2- 13.3 miles, Avg power 136, Normalized power 149.... 408 Kj
Jan 24- 12.8 miles, Avg power 127, Normalized power 165.... 413 Kj
Feb 2- 13.3 miles, Avg power 136, Normalized power 149.... 408 Kj
So the question is where did your 413 kJ number come from?
#6
Thread Starter
Council of the Elders
Joined: Jul 2008
Posts: 3,759
Likes: 3
From: Omaha, NE
Bikes: 1990 Schwinn Crosscut, 5 Lemonds
Work (J) equals power (W) times time (s). It doesn't matter how the power was applied; total work is the integral of instantaneous power over the duration of exercise (i.e., linear). For the two cases, 127 W over 49:56 (2996 seconds) is 380.5 kJ. 136 W gives 408 kJ.
So the question is where did your 413 kJ number come from?
So the question is where did your 413 kJ number come from?
Last edited by billydonn; 02-05-12 at 04:30 PM.
#7
Senior Member

Joined: Apr 2006
Posts: 4,608
Likes: 506
From: Albuquerque, NM
You can write or publish it as many ways as you want; it doesn't add any more value. What I was asking was how was the data measured, recorded, stored, and manipulated. Errors in any of those could cause errors in the displayed average power and work. In your case, it's clear there's an error in the calculated work. Without examining the data train, there's no way of knowing for sure where that's coming from. You might want to start by checking total work against the product of average power and time to see how many are off.
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