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Same Wattage: Headwind vs Tailwind

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Same Wattage: Headwind vs Tailwind

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Old 05-14-25 | 10:06 AM
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Originally Posted by mschwett
yes, and the force which acts/depends on mass is gravity, so the root cause of moving downhill at all is gravity! that was my initial and subsequent point, despite being well aware that the rate of acceleration from gravity is not dependent on mass. i remember that much physics

with dramatically reduced gravity but similar aerodynamic friction (say inside a habitat on the moon), the result would be different.
In practical terms, the actual variables involved here are mass, air resistance and rolling resistance. Of those variables, mass is the most important when comparing riders on similar bikes.

Tandems are a good example of this. Roughly double the mass of a single rider, but with almost equal air resistance. With twice the momentum and potential energy, tandems reach a much higher terminal speed.
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Old 05-14-25 | 10:41 AM
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Originally Posted by PeteHski
In practical terms, the actual variables involved here are mass, air resistance and rolling resistance. Of those variables, mass is the most important when comparing riders on similar bikes.
I can confirm, as just about everyone I ride with is considerably heavier. In order to keep up with them downhill, I need to be more aero, more skilled, and more on my pedals out of each turn.

Steady state downhill coasting speed is a simple static force balance. On one side is:

weight * grade

On the other side is:

(rolling resistance * speed) + (drag coefficient * frontal area * 1/2 air density * speed^2)

A heavier rider descends faster because body mass scales more quickly than frontal area.

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Old 05-14-25 | 10:55 AM
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Originally Posted by mschwett
yes, and the force which acts/depends on mass is gravity, so the root cause of moving downhill at all is gravity! that was my initial and subsequent point, despite being well aware that the rate of acceleration from gravity is not dependent on mass. i remember that much physics

with dramatically reduced gravity but similar aerodynamic friction (say inside a habitat on the moon), the result would be different.
Assume a spherical cow in a vacuum.....
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Old 05-14-25 | 02:39 PM
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Originally Posted by PeteHski
It depends how you look at it.

If both riders had the same mass then any difference in speed would be due entirely to differences in aerodynamic drag and rolling resistance.

But if one rider was significantly heavier they would roll faster even despite a potential increase in aero drag. Mass is the dominant factor in the equation. Changes in mass affect rolling speed in a cubic function, while aerodynamic drag affects speed in a square function.

So really it is mass which makes fatter riders roll faster on descents unless they have a parachute on the bike!
Why do changes in mass have a cubic function? Force due to gravity is linear with mass, so I must be missing something obvious?
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Old 05-14-25 | 06:04 PM
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Originally Posted by PeteHski
One of the main differences will be crank inertia. Similar to when climbing. Slower speeds mean lower crank inertia.
Perhaps I should have stated same power with the same cadence.
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Old 05-14-25 | 06:08 PM
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Originally Posted by PeteHski
I find one of the advantages of riding with a power meter is that when you can see your power output then you stop worrying about the resultant speed.
But that's my question. Riding the SAME POWER, for example 180 watts in a headwind vs. 180 watts in a tailwind. It may be all in my head, but forget speed, it feels more taxing to my legs with the headwind than tailwind with the same wattage output.
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Old 05-14-25 | 06:13 PM
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Went out on a gusty day with the intent to keep at a fixed power and approximate heart rate. Result, it was a dismal failure. I pushed into the wind at about 190 W and with the tailwind, pushed even harder trying to get a PR on a 3 mile stretch at 280 W. I didn’t get the PR so it was a failure.
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Old 05-14-25 | 06:18 PM
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Originally Posted by eduskator
The word perceived is the key here. It does not feel the same, no, mainly because you're battling against an element. At least, not for the average joe. Different conditions means different perceived efforts. 300w at 30kph against a headwind does not feel the same as 300w at 40kph with a tailwind. One is fun, the other isn't. This is when and why mental resilience is key in endurance sport. The magic happens between your ears.
The more I think about it, the more I think you are right and hit the nail on the head... perhaps mine.
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Old 05-14-25 | 06:27 PM
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Originally Posted by Racing Dan
Do you actually own a power meter?

Ime, ppl rider harder into the wind to maintain speed, just like they ride harder up hill. Thats why they "think" hills and headwind is hard. They are not compensating enough, ie. not slowing down enough. If you own both, try pairing a power meter and a HR monitor and Im betting your HR is the same no matter if you do 150w at 12 mph into the wind, 150w in a tail wind at 24 mph or 150w up a hill, as long as you maintain the same cadence. One watt is one watt, no matter what you do.
Of course I own a power meter. That's why I asked the question. The ride that caused me to write this had me riding the same power both into a headwind and a tailwind. I do like your idea of observing my HR in both situations. I didn't think of that.
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Old 05-14-25 | 08:49 PM
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Originally Posted by genejockey
Assume a spherical cow in a vacuum.....
My HS physics teacher clearly had issues with cats. Cats in a vacuum, a 15 lb cat hanging from a clothesline, a cat launched at a 30 degree angle, the coefficient of friction between the cat and the floor. Of course the infamous cat that drops just as the blowgun dart is fired. Can't remember his name, but he rode a BMW motorcycle in the 70's, which nobody did.
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Old 05-15-25 | 12:49 AM
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Originally Posted by terrymorse
I can confirm, as just about everyone I ride with is considerably heavier. In order to keep up with them downhill, I need to be more aero, more skilled, and more on my pedals out of each turn.

Steady state downhill coasting speed is a simple static force balance. On one side is:

weight * grade

On the other side is:

(rolling resistance * speed) + (drag coefficient * frontal area * 1/2 air density * speed^2)

A heavier rider descends faster because body mass scales more quickly than frontal area.
Steady state, I agree this is a good representation of the physics. What I am struggling with a bit is that lighter riders also tend to accelerate more slowly at the start of descents. Perhaps they just don’t put as much power into getting up to speed and if everyone coasted they would be more on a par.
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Old 05-15-25 | 08:09 AM
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Originally Posted by choddo
Steady state, I agree this is a good representation of the physics. What I am struggling with a bit is that lighter riders also tend to accelerate more slowly at the start of descents. Perhaps they just don’t put as much power into getting up to speed and if everyone coasted they would be more on a par.
Think of it as an advantage that's always there, but which gets larger as speeds increase. I've found that even coasting of softpedaling, I coast away from lighter riders on descents.
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Old 05-15-25 | 09:35 AM
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Originally Posted by choddo
Steady state, I agree this is a good representation of the physics. What I am struggling with a bit is that lighter riders also tend to accelerate more slowly at the start of descents. Perhaps they just don’t put as much power into getting up to speed and if everyone coasted they would be more on a par.
If the riders start the descent from a standstill, then they will accelerate at the same rate initially.
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Old 05-15-25 | 11:47 AM
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Originally Posted by choddo
Why do changes in mass have a cubic function? Force due to gravity is linear with mass, so I must be missing something obvious?
Very good question! Having thought more about it, I’m not sure it’s correct either. Here is the source of that specific info for reference.

https://www.cyclist.co.uk/in-depth/f...ownhill-faster

If we think in terms of max rolling speed, then terminal velocity is actually proportional to the square root of the mass. So not linear (as it is with the force) but certainly not cubic. Similarly, terminal velocity is also inversely proportional to the square root of CdA.

I think what they might have meant was that frontal area only scales in proportion to mass to the power of 1/3. So a large increase in mass only results in a small increase in air resistance.

I checked a few other articles but there were so many fundamental misunderstandings of the physics (some even coming from alleged post-,grad theoretical physicists!) that I gave up in the end. In particular, the classic feather vs cannonball freefall scenario becomes a large red herring once air and rolling resistance is added. That scenario also says nothing about the differences in potential energy (mgh) and momentum (mv) between the feather and cannonball.
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Old 05-15-25 | 11:53 AM
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Originally Posted by choddo
Steady state, I agree this is a good representation of the physics. What I am struggling with a bit is that lighter riders also tend to accelerate more slowly at the start of descents. Perhaps they just don’t put as much power into getting up to speed and if everyone coasted they would be more on a par.
For sure they would both start off rolling from a standstill with the same initial acceleration, but air resistance is building in proportion to the square of speed, so will soon start to take effect and slow the lighter rider more.
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Old 05-15-25 | 11:54 AM
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Originally Posted by PeteHski
I think what they might have meant was that frontal area only scales in proportion to mass to the power of 1/3. So a large increase in mass only results in a small increase in air resistance.
I think the frontal area should (roughly) scale with mass to the 2/3 power.
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Old 05-15-25 | 12:16 PM
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Originally Posted by tomato coupe
I think the frontal area should (roughly) scale with mass to the 2/3 power.
mmmmm…. I thought it was approx 1/3, but maybe I’m thinking of the combined CdA scaling.

Some info here:-

https://pubmed.ncbi.nlm.nih.gov/11560092/


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Old 05-15-25 | 12:29 PM
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Originally Posted by Bassmanbob
Perhaps I should have stated same power with the same cadence.
Crank inertial load is still lower when riding into a headwind at the same power and cadence ie in a lower gear ratio. CIL is really the only mechanical difference in that scenario.
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Old 05-15-25 | 12:56 PM
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Originally Posted by PeteHski
mmmmm…. I thought it was approx 1/3, but maybe I’m thinking of the combined CdA scaling.

Some info here:-

https://pubmed.ncbi.nlm.nih.gov/11560092/
It looks like they came up with an empirical value of .76. The rough estimate* comes from:

area ~ r^2
mass ~ r^3
therefore, area ~ mass^(2/3)

* assuming a spherical cow
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Old 05-15-25 | 01:15 PM
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Originally Posted by tomato coupe
If the riders start the descent from a standstill, then they will accelerate at the same rate initially.
assuming none peddles won't they both just have the same acceleration? the only acceleration i can think of is gravity, also assuming they both experience the same effect due to wind.
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Old 05-15-25 | 02:39 PM
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Originally Posted by tomato coupe
It looks like they came up with an empirical value of .76. The rough estimate* comes from:

area ~ r^2
mass ~ r^3
therefore, area ~ mass^(2/3)

* assuming a spherical cow
Yes, and then CdA drops back to 0.31 when A is combined with Cd, which hardly changes with mass.
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Old 05-15-25 | 02:40 PM
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Originally Posted by spelger
assuming none peddles won't they both just have the same acceleration? the only acceleration i can think of is gravity, also assuming they both experience the same effect due to wind.
No
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Old 05-15-25 | 02:59 PM
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Originally Posted by PeteHski
No
well that was concise.

after gravity what are the other forces being applied that would contribute to acceleration?
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Old 05-15-25 | 03:11 PM
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Originally Posted by spelger
well that was concise.

after gravity what are the other forces being applied that would contribute to acceleration?
Rolling resistance of your tires, and how freely your wheels spin. That's leaving aside the aerodynamics.
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Old 05-15-25 | 03:17 PM
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Originally Posted by spelger
well that was concise.

after gravity what are the other forces being applied that would contribute to acceleration?
That's because we have literally just been discussing this in some detail. Try reading the last few thread pages.
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