Sensor Placement on the front wheel
#102
Thanks njkayaker.
This what I was trying to conclude earlier. The 'deformed' radius is what must be used for the radius calculation. Agreed that in a properly inflated tire, it may not be different from the unloaded tire radius. It will most likely also be slightly different from tire manufacturer to tire manufacturer for the same size tire.
This what I was trying to conclude earlier. The 'deformed' radius is what must be used for the radius calculation. Agreed that in a properly inflated tire, it may not be different from the unloaded tire radius. It will most likely also be slightly different from tire manufacturer to tire manufacturer for the same size tire.
#103
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Bikes: Kestrel Talon
Ok, I made a mistake in my assumption, and then compounded it by trying to extend a 2 dimensional model to a complex multidimensional reality. For auto tires, it turns out that there is a derivation and experimental data to back it up (quoted from an engineering forum: https://eng-tips.com/viewthread.cfm?qid=94153):
"Distance traveled is somewhere in between what the free radius and the loaded radius predict. There's a derivation given in "Mechanics of Pneumatic Tires", that identifies the tread as being compressed in the contact patch and also over the zones immediately before and after the contact patch. It goes on to talk in terms of effective radius and effective deflection that differ from the loaded radius and actual deflection respectively. And it mentions that very little longitudinal slip occurs within the contact patch (assuming no acceleration/braking), hence there's little wear under conditions of rolling in a straight line.
Eventually the discussion gets around to providing some experimental data, with the actual distance traveled measured for a bias tire given at 96% of what the free radius predicts but the loaded radius being only 94% of the free radius (yes, this dates my reference material somewhat). For radials, it gives 98% distance traveled with the loaded radius being only 92% of loaded radius. Data for more recent tires may differ in the specific percentages, but I'd certainly expect the general relation to hold."
Assuming the data for bicycle tires would show a similar result, then my simplistic model doesn't work well in the real world, and it looks like measuring rollout is the only solution - with a loaded measurement giving the best result. mea culpa.
JB
edit: while I'm eating crow, I should also point out that I did make an error with the geometry in my 2d model. I'd assumed that the deflection acts like a secant across the circle, but that the circumference would stay the same. The only way this could work is if the radius of the circular part of the deflected tire has a radius LARGER than the original, unloaded radius. Obviously, that completely invalidates my assumption of no stretching or compression going on - the tire would have to stretch along the circumference to account for the larger radius, but then compress along the flat part to achieve the same overall circumference. mea culpa, mea culpa. I'm going to go enjoy my crow dinner now (and thanks to my son's geometry teacher for pointing out that error!).
"Distance traveled is somewhere in between what the free radius and the loaded radius predict. There's a derivation given in "Mechanics of Pneumatic Tires", that identifies the tread as being compressed in the contact patch and also over the zones immediately before and after the contact patch. It goes on to talk in terms of effective radius and effective deflection that differ from the loaded radius and actual deflection respectively. And it mentions that very little longitudinal slip occurs within the contact patch (assuming no acceleration/braking), hence there's little wear under conditions of rolling in a straight line.
Eventually the discussion gets around to providing some experimental data, with the actual distance traveled measured for a bias tire given at 96% of what the free radius predicts but the loaded radius being only 94% of the free radius (yes, this dates my reference material somewhat). For radials, it gives 98% distance traveled with the loaded radius being only 92% of loaded radius. Data for more recent tires may differ in the specific percentages, but I'd certainly expect the general relation to hold."
Assuming the data for bicycle tires would show a similar result, then my simplistic model doesn't work well in the real world, and it looks like measuring rollout is the only solution - with a loaded measurement giving the best result. mea culpa.
JB
edit: while I'm eating crow, I should also point out that I did make an error with the geometry in my 2d model. I'd assumed that the deflection acts like a secant across the circle, but that the circumference would stay the same. The only way this could work is if the radius of the circular part of the deflected tire has a radius LARGER than the original, unloaded radius. Obviously, that completely invalidates my assumption of no stretching or compression going on - the tire would have to stretch along the circumference to account for the larger radius, but then compress along the flat part to achieve the same overall circumference. mea culpa, mea culpa. I'm going to go enjoy my crow dinner now (and thanks to my son's geometry teacher for pointing out that error!).
Last edited by jonathanb715; 08-25-10 at 07:48 PM.
#104
Bike ≠ Car ≠ Ped.

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Bikes: Some bikes. Hell, they're all the same, ain't they?
#107
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From: Far beyond the pale horizon.
Yes, plus these important facts:
The "rolling circumference" (the standard term for this) is equal to pi*2*r, where r is the height of the center of the hub to the ground.
The "rolling circumference" is exactly the horizontal distance the center of the hub moves in a complete rotation of the wheel.
This is what the "theory" predicts.
Last edited by njkayaker; 08-26-10 at 10:00 AM.
#108
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From: Far beyond the pale horizon.
I'm gonna dump on "poor" jonathanb715 a bit more to make some points which I think are important to make these kinds of discussions successful.
That is a reference I provided. If you didn't realize that, it means you ignored people's counter argument.
Note that for this argument, it would have been very strange if this issue had not come up before. The fact that you did not provide any references to support your position is telling. If you are going to have these kinds of arguments, providing references is important to do.
This is basically "waving your hands and saying it doesn't matter". I said earlier that the difference was going to be on the order of 1%. If you are going to have an argument about a theoretical issue, it's important to keep issues of measurement errors out of the discussion.
The "theory" predicts a difference on the order of 1%. If your measurements can't reliably show that difference, then your measurement technique is not sensitive enough!
No, it seems more reasonable to expect that a deflated tire defines the lower bound for the effect of reduced pressure on the "rolling circumference". The effect doesn't have to be "identical": it just has to be "close enough".
Your mistake here was not indicating what you thought the effect would be. You rejected it out-of-hand with "that doesn't mean the effect is identical", which might be true but might not be! It's possible that the effect is "identical" enough and you provided nothing to support your rejection of it's relevance.
You rejected it not because you had a reason (you didn't provide any) but because you could not conceive of being wrong!
The arrogance here (and in other posts) is noticeable. If you want to be arrogant, don't ever be wrong!
The only place where what the "point" does is smack dab in the middle of the contact patch directly under the hub. What the point does in any other place has no effect on the "rolling circumference" measurement. (The point could take a trip to France and it would not matter).
It's important to understand that the point in the center of the contact patch directly under the hub is a point on a circle of a rigid (nondeformable) wheel, the circumference is less than the tire circumference. The circumference of that virtual wheel is the circle whose radius is the height of the center of the hub from the ground.
You have to be very careful with the tank tread analogy. You did not read my post, where I brought it up, very carefully.
The problem with the tank tread analogy is that you don't have a hub to use that matches the "rotation" of the tread. All the available hubs are too small (this is why I used the analogy). The reason you would not use the tread is because you need a hub to put the magnet on! If you pick a roller on the ground (with the tread in between), you could put the magnet there and input pi*2*r into the computer (r is the height of the hub axis). The length of the tread doesn't matter (and is an unusable measurement).
===============
Note that I was wrong in saying that "circumference" only applies to circles (but that's a minor thing). It still seems weird to me to apply it to non-circles. Note that I never disagreed that the circumference of the tire is constant (that seems obvious to me).
Ok, I made a mistake in my assumption, and then compounded it by trying to extend a 2 dimensional model to a complex multidimensional reality. For auto tires, it turns out that there is a derivation and experimental data to back it up (quoted from an engineering forum: https://eng-tips.com/viewthread.cfm?qid=94153):
Note that for this argument, it would have been very strange if this issue had not come up before. The fact that you did not provide any references to support your position is telling. If you are going to have these kinds of arguments, providing references is important to do.
I'd just like to point out that my difference in averages was very small - well under 1% (2mm), and the difference in samples was somewhat larger (+-3mm). Even adding the difference in between the largest outliers gives you a change in rolliout of less than 0.5% - still not real reliable, but probably accurate and definitely not worth worrying about when setting your computer. Yes, more samples would make this a more valid data set. FWIW, I'm the only one who bothered to post any data at all.
Your mistake here was not indicating what you thought the effect would be. You rejected it out-of-hand with "that doesn't mean the effect is identical", which might be true but might not be! It's possible that the effect is "identical" enough and you provided nothing to support your rejection of it's relevance.
You rejected it not because you had a reason (you didn't provide any) but because you could not conceive of being wrong!
Sigh. When measuring circumference or rollout, you are measuring from the same point on the outside of the tire to the exact same point. That point does have to cover that flat part as the tire rolls through, then it lifts off the ground and will follow the circle until it comes in contact again at the beginning of the flat section - but you don't measure rollout when it gets there there, you measure it at the center point , where the hub is closest to that point (assuming that's where you started). If you insist on using circular measurements (radius) for non-circular shapes, you will get results like this.
The only place where what the "point" does is smack dab in the middle of the contact patch directly under the hub. What the point does in any other place has no effect on the "rolling circumference" measurement. (The point could take a trip to France and it would not matter).
It's important to understand that the point in the center of the contact patch directly under the hub is a point on a circle of a rigid (nondeformable) wheel, the circumference is less than the tire circumference. The circumference of that virtual wheel is the circle whose radius is the height of the center of the hub from the ground.
Think back to the tank tread. Does it have a circumference? Yup. Can you make it into a circle? Pretty close, as long as the plates are small and the hinges between them are flexible. Does that change it's circumference? Nope, unless the tread shrinks or stretches in the process. In that respect the tread acts a lot like a bicycle chain.
The problem with the tank tread analogy is that you don't have a hub to use that matches the "rotation" of the tread. All the available hubs are too small (this is why I used the analogy). The reason you would not use the tread is because you need a hub to put the magnet on! If you pick a roller on the ground (with the tread in between), you could put the magnet there and input pi*2*r into the computer (r is the height of the hub axis). The length of the tread doesn't matter (and is an unusable measurement).
===============
Note that I was wrong in saying that "circumference" only applies to circles (but that's a minor thing). It still seems weird to me to apply it to non-circles. Note that I never disagreed that the circumference of the tire is constant (that seems obvious to me).
Last edited by njkayaker; 08-26-10 at 11:09 AM.
#110
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From: Far beyond the pale horizon.
With the right number, the difference is about 1 inch, which is a difference people should be able to measure accurately and reliably.
Last edited by njkayaker; 08-26-10 at 10:55 AM.
#111
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For the 23 size Continental, front mounted, folding (Kevlar bead), 110psi, same load:
Gatorskin: 2096 (consistent for 4 different tires)
GP4000S: 2103 (only one tire)
These values result in matched distance measurements to better than .01mi for a 8.55mi route. 14 data points for the GP, hundreds for the Gatorskin.
#112
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It's important to understand that the point in the center of the contact patch directly under the hub is a point on a circle of a rigid (nondeformable) wheel, the circumference is less than the tire circumference. The circumference of that virtual wheel is the circle whose radius is the height of the center of the hub from the ground.
Uh, the data from the engineering forum regarding car tires doesn't support that assertion either.
"Distance traveled is somewhere in between what the free radius and the loaded radius predict."
JB
Last edited by jonathanb715; 08-26-10 at 11:15 AM.
#113
Bike ≠ Car ≠ Ped.

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Bikes: Some bikes. Hell, they're all the same, ain't they?
Aren't you guys finished yet?
You (meaning "everyone here") could've gone out and done your own rollout tests by now.
Now, either get out and ride or get back to work.
You (meaning "everyone here") could've gone out and done your own rollout tests by now.
Now, either get out and ride or get back to work.
#114
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For what it's worth (???) I believe some auto tire pressure monitors work by measuring wheel rotational speed -- an under-inflated tire can be found because it will be spinning a little faster than the others.
I'm still a little cloudy on the mechanics of why this all works.
I'm still a little cloudy on the mechanics of why this all works.
#115
Bike ≠ Car ≠ Ped.

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From: Washington, DC
Bikes: Some bikes. Hell, they're all the same, ain't they?
Other TPS systems use electronic sensors inside the wheels, which transmit their pressure readings by radio to the car computer.
I'm still a little cloudy on the mechanics of why this all works.
What people are forgetting is that the radius we're looking at is ALWAYS straight from the hub to the ground. Nothing else matters.
FWIW, on the flat car tire tangent, this is one reason why car manufacturers recommend putting the "donut" compact spare wheel on an undriven axle -- if you flatted a front tire on a front-wheel-drive car, you need to replace that wheel with one of the good ones from the rear and put the donut in back. Having two different circumferences on the driven wheels makes the differential work harder than necessary (among other things). If it's an all-wheel-drive car, the best thing is to put it on a flatbed (or carry a can of fix-a-flat, or use a full-size spare).
#116
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"Distance traveled is somewhere in between what the free radius and the loaded radius predict."
Just sayin'.
JB
#117
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I think that's an oversimplification. As is stated above, "Distance traveled is somewhere in between what the free radius and the loaded radius predict."
#118
Bike ≠ Car ≠ Ped.

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From: Washington, DC
Bikes: Some bikes. Hell, they're all the same, ain't they?
Now shut up and do your stupid rollout test if you care so much. I've got lunch to eat.
#119
For a bit of perspective:
https://xkcd.com/386/
https://xkcd.com/386/
#120
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From: S.E. Michigan
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For what it's worth (???) I believe some auto tire pressure monitors work by measuring wheel rotational speed -- an under-inflated tire can be found because it will be spinning a little faster than the others.
I'm still a little cloudy on the mechanics of why this all works.
I'm still a little cloudy on the mechanics of why this all works.
Basically, the actual circumference is the over all wheel and tire combined. The effective circumference, what will be measured, is that of the deformed tire under your weight.
Really? five pages?
#121
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From: Far beyond the pale horizon.
Originally Posted by njkayaker
It's important to understand that the point in the center of the contact patch directly under the hub is a point on a circle of a rigid (nondeformable) wheel, the circumference is less than the tire circumference. The circumference of that virtual wheel is the circle whose radius is the height of the center of the hub from the ground.
"Distance traveled is somewhere in between what the free radius and the loaded radius predict."
JB
Anyway, what you are talking about is a refinement of understanding what is going on. You have to clear what I am saying as a starting point.
Pointing out that reference as showing an "error" in what I was saying proves that you still don't get the main point!
Last edited by njkayaker; 08-26-10 at 12:10 PM.
#122
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#124
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From: Far beyond the pale horizon.
Originally Posted by Bike Lover
The effective circumference, what will be measured, is that of the deformed tire under your weight.
(He's only saying what I've been arguing for pages anyway. That is, his comment is a "drive by posting" that doesn't add anything to the discussion (he clearly hasn't read the posts in the thread!).
Anyway, the issue his post does not address is how that value relates to the circumference of the tire!
#125
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And it may be even less of a difference for a lower mass lower speed bicycle tire relative to an automotive tire.




